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Lesson 11 of 14

Sound Waves: Characteristics and Applications · Lesson 11 of 14

Echo

An echo is a reflected sound heard separately after a sufficient delay, making round-trip distance calculations possible.

Learning Objectives

• Define echo. • Explain why echoes are not heard in every room. • Use the minimum time separation criterion. • Calculate minimum reflecting distance. • Solve round-trip echo problems.

A shout near a distant cliff can return as a clearly separate repetition. The original sound has travelled to the reflecting surface and then back to the listener.

Echo

Definition
Echo

A reflected sound that returns to the listener after the original sound and is heard as a separate sound.

The human auditory system requires roughly 0.1 s between two arriving sounds for them to be distinguished separately in the echo discussion. If the reflection returns sooner, it merges perceptually with the original rather than forming a clearly distinct echo.

Minimum Distance for a Distinct Echo

Using 340 m s⁻¹, sound travels 34 m during 0.1 s. But this is the full outward-and-return path. The reflecting surface is therefore half that distance away.

Echo DistanceLaTeX
The factor of two is required because the measured time includes travel to the reflector and back.
Echo Is a Round Trip Listener Wall Sound travels to the wall Reflected sound returns Distance to wall = vt / 2
Echo round tripThe sound covers the source-to-wall distance twice before it returns.
Worked Example: Minimum Echo Distance

Problem
Using v = 340 m s⁻¹ and minimum separation time 0.1 s, find the minimum reflecting distance.

  1. 1.Calculate total sound path: vt = 340 × 0.1 = 34 m.
  2. 2.The 34 m includes outward and return travel.
  3. 3.Divide by 2: d = 17 m.
  4. 4.The reflecting surface must be about 17 m away under these conditions.
Worked Example: Corridor Echo

Problem
A clap produces an echo after 0.5 s. If sound speed is 340 m s⁻¹, find the distance to the wall.

  1. 1.Use d = vt/2.
  2. 2.Substitute v = 340 m s⁻¹ and t = 0.5 s.
  3. 3.d = 340 × 0.5 ÷ 2.
  4. 4.d = 85 m.
  5. 5.The wall is 85 m away.
Worked Example: Required Echo Delay

Problem
An experiment requires an echo at least 0.2 s later. If v = 343 m s⁻¹, find the minimum reflector distance.

  1. 1.Use d = vt/2.
  2. 2.d = 343 × 0.2 ÷ 2.
  3. 3.343 × 0.2 = 68.6 m for the round trip.
  4. 4.Divide by 2 to obtain 34.3 m.
  5. 5.The reflector must be at least about 34.3 m away.
Highest-Attention Idea

Echo numericals nearly always involve round-trip travel. If you forget to divide vt by two, you calculate the total path length rather than the one-way distance.

Quiz

Quick check

Which description best matches Echo?

Quick check

Which term matches this description: A reflected sound that returns to the listener after the original sound and is heard as a separate sound.

Quick check

Which statement is a key takeaway from this lesson?

Quick check

Which additional statement is also a key takeaway from this lesson?

Quick check

Which further statement is also a key takeaway from this lesson?

Practice Problems

Check Your Understanding
  1. Why is a distinct echo usually not heard in a small room?
  2. Calculate reflector distance for an echo time of 1.0 s when v = 340 m s⁻¹.
  3. Why do hard smooth surfaces give stronger echoes?
  4. Why do rough surfaces make clear echoes less likely?

Key Takeaways

Key Takeaways

• An echo is a reflected sound heard separately from the original sound. • A sufficient time gap is needed for the ear to distinguish the reflected sound. • Because sound travels to the reflecting surface and back, echo calculations involve a round-trip distance. • Distance to the reflecting surface can be determined from sound speed and measured echo time.