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Lesson 8 of 8

Proportional Reasoning-1 · Lesson 8 of 8

Chapter Summary and Practice

“Revisit all seven lessons in learning order, compare methods, solve mixed revision problems and complete the source Binairo enrichment puzzles.”

Learning Objectives

• Recover every main ratio and proportion idea from Lessons 1–7. • Choose between scaling, simplification, sharing and conversion. • Use formulas with meaning and check assumptions. • Solve mixed problems with complete unit and reasonableness checks. • Apply the three Binairo rules in the final enrichment activity.

After a gap, ratio questions can look similar even when they ask for different things. One asks you to resize a picture, another to divide a total, and another to compare prices for equal amounts. This revision page rebuilds the ideas in the order you learned them. Use it to recover the meaning behind each method, not just the arithmetic steps. A reliable solution begins by identifying the quantities and the relationship between them.

Read each reminder, pause at the worked examples and choose a method before looking at the solution. Finish with the mixed questions, then use the Binairo activity to practise careful logical reasoning.

7.1 Observing Similarity in Change

From Lesson 1: proportional change multiplies corresponding quantities by one common factor. When the same image is resized without cropping, width and height must use that same factor to preserve its proportions. A factor above 1 enlarges it, while a positive factor below 1 reduces it.

The sizes 60 by 40, 30 by 20 and 90 by 60 share the same proportions. Subtracting 20 from both dimensions of 60 by 40 instead gives 40 by 20. The factors 2/3 and 1/2 differ, so equal subtraction is not the same as proportional scaling.

The practical method is: divide new by old for one corresponding quantity, then multiply the other old quantity by that factor. Being rectangular is not by itself evidence that an image has been resized proportionally.

Revision: proportional resizing

Problem
A 24 cm by 16 cm picture is reduced to width 9 cm. Find the new height.

7.2 Ratios

From Lesson 2: a ratio a : b compares two quantities in a stated order. For every a units of the first, there are b units of the second. The numbers are called terms. Reversing the comparison reverses the terms.

Equivalent ratios are produced by multiplying or dividing both terms by the same positive factor. The actual amounts can differ: 3 : 2, 6 : 4 and 9 : 6 express the same relationship. A part-to-part ratio is not automatically a part-to-whole comparison.

7.3 Ratios in their Simplest Form

For whole-number terms, divide both by their HCF. Thus 72 : 96 simplifies by 24 to 3 : 4. If the remaining terms still share a factor larger than 1, the ratio is not yet simplest.

Two ratios are in proportion when they are equivalent; their simplest forms match. Write a : b :: c : d. Keep quantity order consistent: width : height must be compared with width : height, not height : width.

Revision: equivalent or different?

Problem
Compare 18 : 24, 30 : 40 and 18 : 30.

7.4 Problem Solving with Proportional Reasoning

From Lesson 3: use ratios to compare quantities fairly. A lemonade recipe keeps the same sweetness when both its glass count and sugar amount scale together, assuming equal glass and spoon sizes. A coffee mixture’s strength depends on decoction relative to milk, not the amount of decoction alone.

Regular coffee has decoction : milk = 3 : 7. A mixture 24 : 56 is equivalent. Ratios 1 : 2 and 3 : 10 are respectively stronger and lighter than regular coffee. Compare at a common milk amount or common total before judging.

For missing terms, use the factor attached to a known pair. From 14 : 21 to 6 : x, the factor is 3/7, so x = 9. Fractional factors and fractional ratio terms are allowed.

Equal additions generally change a ratio. Neelima and her mother change from ages 3 and 30 to 12 and 39: the ratio changes from 1 : 10 to 4 : 13, while the difference remains 27 years. This distinguishes an additive relationship from a proportional one.

For visual activities, compare corresponding dimensions and use one scale factor for every measured length. In a repeating brick pattern, count one complete repeat unit: repeating it multiplies both colour counts equally. Different-sized drawings can all be valid when their corresponding ratios agree.

Trairasika — The Rule of Three

From Lesson 4: write c = fa and d = fb for one common factor f. Then c/a = d/b. Multiplying by ab produces ad = bc. For the positive quantities in these problems, this cross-product condition tests a proportion as well as helping solve it.

If d is unknown, divide by a to obtain d = bc/a. The traditional names are pramāṇa for a, phala for b, ichchhā for c and ichchhāphala for d. The structure means “given result times requested measure, divided by given measure.”

Proportion and the unknown fourth termLaTeX

Before calculating, align corresponding units. Time in minutes must match time in minutes; a weight in grams must match the other weight in grams. Two different quantities, such as time and distance, may naturally have different units from each other.

Check that direct proportion applies. At constant speed, more time gives proportionally more distance. For a fixed journey, higher speed instead gives less time. Package prices may also fail to scale with volume. Cross multiplication cannot make an unsuitable direct-proportion model valid.

Retain the context checks from the activities: recipe scaling uses the full intended number of servings; price comparisons use equal amounts; brick estimates use the full built wall length with matching height and thickness; approximate annual distances give approximate weekly distances.

Revision: units before proportion

Problem
At constant speed, a vehicle covers 90 km in 150 minutes. Find the distance in four hours.

7.5 Sharing, but Not Equally!

From Lesson 5: when a whole x is split in ratio m : n, add the ratio terms. There are m+n equal parts, so one part is x/(m+n). Multiply by m or n to find each share.

For 42 counters in ratio 4 : 3, there are seven parts of six counters each. The shares are 24 and 18. Verify both their sum and their ratio. The denominator for a fraction of the whole is m+n, not just the other ratio term.

Sharing a totalLaTeX

For changing mixtures, first calculate the actual component amounts. Then identify which stays fixed. In 40 kg of 3 : 1 sand and cement, the amounts are 30 kg and 10 kg. To reach 5 : 2 by adding cement, keep sand at 30 kg, find required cement 12 kg, and add only 2 kg.

An added whole container is not necessarily one ratio part. In a full bucket of 3 : 5 red and yellow paint, the bucket contains eight ratio parts. Adding another equally sized full bucket of yellow gives 3 : 13. Confirm that container capacities match.

A measurement may have fractional parts, but indivisible objects may prevent an exact whole-object split. Interpret the arithmetic according to what is being shared.

Total = 40 mLBlue: 3 partsYellow: 5 parts8 equal parts altogether
The whole is the sum of the ratio parts
Revision: before-and-after mixture

Problem
Blue : yellow = 3 : 5 in 40 mL. Add 20 mL yellow. Find the new ratio.

7.6 Unit Conversions

From Lesson 6: a conversion changes the unit description of a fixed amount. Predict whether the numerical count should increase or decrease, then use a factor for the correct kind of measurement. Area conversion must use square units, not the length factor alone.

QuantityConversion reminder
Length1 m ≈ 3.281 ft
Area1 m² ≈ 10.764 ft²; 1 acre = 43,560 ft²
Area1 hectare = 10,000 m² ≈ 2.471 acres
Volume1 mL = 1 cc = 1 cm³; 1 L = 1000 mL
TemperatureF = (9/5)C + 32; C = (5/9)(F − 32)

The factors written with ≈ are rounded. Use an approximate answer when they are used. A litre is a volume unit and is not automatically a kilogram of every substance.

Temperature conversion has a fixed offset: 0°C corresponds to 32°F. Therefore Celsius and Fahrenheit readings are not directly proportional. In the reverse formula, subtract 32 before multiplying by 5/9.

Revision: temperature is not simple scaling

Problem
Find Fahrenheit values for 20°C and 40°C. Are they in ratio 1 : 2?

Figure it Out

From Lesson 7: first choose the kind of reasoning. Juice comparisons use ratio simplification; buses use capacity per bus and rounding up; crowding uses people per area; the crane example uses a fraction of the whole; and the saffron example uses a fractional scale factor.

The age question distinguishes final age from elapsed years. The given gold-to-water exercise compares masses at equal volume. Farming and land-cost questions require area conversions; the tap question requires volume conversion and constant flow. The tractor question compares time for a fixed job.

The coin challenge combines three operations: divide total mass in a ratio, convert grams to kilograms, and multiply each mass by its corresponding price before adding. Use the stipulated data as a model and do not confuse material cost with monetary value.

What the question asksA useful first moveCheck before finishing
Same proportions at a new sizeFind new ÷ old for one quantityApply the same factor to every corresponding quantity.
Are two ratios equivalent?Simplify by HCF or compare cross productsKeep the quantity order the same.
A missing fourth quantityModel a valid proportionMatch units and check the direction of change.
Shares of a known wholeAdd the ratio termsShares add to the whole and have the requested ratio.
Only one ingredient is addedRecover original component amountsKeep the other ingredient fixed; subtract the amount already present.
Fair price or crowding comparisonCompare at one common amountDo not judge by package price or population alone.
Capacity or different working ratesFind one-unit capacity or fixed-work timeInterpret whole-object and faster/slower constraints.
Mixed revision: seats and interpretation

Problem
Three full buses carry 162 people. How many identical buses carry 204?

Mixed revision: sharing and price units

Problem
Use the stated 7.74 g, 3 : 1 copper–nickel model with prices ₹906/kg and ₹1341/kg. Find its metal cost.

Binairo

After the revision, try this logic activity, also called Takuzu. Fill each empty cell with a horizontal line H or a vertical line V. In these six-by-six grids, every row and every column must contain exactly three of each symbol.

Do not put three identical symbols consecutively in a row or column. Every completed row must differ from every other row, and every completed column must differ from every other column. A row is allowed to match a column: the uniqueness comparisons are within rows and within columns.

StarterOne valid solutionThree of each symbol per row and column.
Binairo starter puzzle and one valid completed solution
A first forced move in the starter

Problem
The starter’s third row already has V in columns 1, 3 and 6. What goes in the other cells?

What “unique rows” means

The rule forbids duplicate completed rows and duplicate completed columns. It does not itself guarantee that the starting puzzle has only one solution. The printed starter admits two valid completions under its clues; the solution shown is one valid completion. Each of the following three practice grids has a unique completion.

Puzzle 1H: horizontal line V: vertical line
Binairo practice puzzle 1: copy the clues and fill the empty cells
Solution row123456
1HVHHVV
2VHVVHH
3VHHVHV
4HVVHVH
5HVHVHV
6VHVHVH
Puzzle 2H: horizontal line V: vertical line
Binairo practice puzzle 2: copy the clues and fill the empty cells
Solution row123456
1HHVVHV
2HVVHVH
3VHHVHV
4HVVHHV
5VHHVVH
6VVHHVH
Puzzle 3H: horizontal line V: vertical line
Binairo practice puzzle 3: copy the clues and fill the empty cells
Solution row123456
1HVHVHV
2VHVHVH
3HVHVVH
4VHVHHV
5HHVVHV
6VVHHVH

Quiz

Quick check

Which resize keeps a 60 by 40 image’s proportions?

Quick check

For positive quantities a : b :: c : d, which equality is correct?

Quick check

A total of 40 is split in ratio 3 : 5. What is the first share?

Quick check

Which calculation converts 68°F to Celsius?

Quick check

Which situation needs a check beyond an ordinary fractional answer?

Practice Problems

Practice Problems
  1. A 60 mm by 40 mm image is enlarged to width 105 mm. Find the proportional height and the simplest width-to-height ratio.
  2. A car covers 90 km in 150 minutes at constant speed. How far does it travel in four hours?
  3. Split 40 mL of paint in blue : yellow = 3 : 5, then find the new ratio after adding 20 mL yellow.
  4. A tap fills 500 mL in 15 seconds. Find the time for 10 L. Also convert 25°C to Fahrenheit and explain why that temperature conversion is not direct proportion.
  5. Using the coin model, divide 7.74 g in the ratio copper : nickel = 3 : 1 and calculate the total cost at ₹906/kg and ₹1341/kg.
Practice 1: worked solution

1. Scale factor = 105/60 = 7/4. Height = 40 × 7/4 = 70 mm. 2. 105 : 70 simplifies to 3 : 2.

Practice 2: worked solution

1. Four hours = 240 minutes. 2. 150 : 90 :: 240 : x gives x = 90 × 240/150 = 144 km.

Practice 3: worked solution

1. The original amounts are 15 mL blue and 25 mL yellow. 2. Yellow becomes 45 mL and blue stays 15 mL. New ratio = 1 : 3; total = 60 mL.

Practice 4: worked solution

1. 10 L = 10,000 mL, a factor of 20. Time = 20 × 15 = 300 seconds = 5 minutes. 2. 25°C gives 25 × 9/5 + 32 = 77°F. 3. The flow problem uses a common scale factor at constant flow; temperature conversion includes adding 32, so the readings are not directly proportional.

Practice 5: worked solution

1. One part is 7.74/4 = 1.935 g. Copper = 5.805 g and nickel = 1.935 g. 2. Convert to kilograms and multiply by the respective prices: ₹5.25933 and ₹2.594835. 3. Total = ₹7.854165 ≈ ₹7.85. Verify the mass total and ratio; this is a material-cost model, not the coin’s monetary value.

Key Takeaways

Key Takeaways

• Proportional change uses one common multiplying factor; equal additions generally do not. • Ratios are ordered comparisons, and equivalent ratios have equal simplest forms and cross products. • The Rule of Three applies after the relationship and corresponding units have been checked. • To share a total, add the ratio terms and find one equal part first. • In changing mixtures, track the unchanged component and distinguish final amount from amount added. • Length, area and volume need appropriate conversion factors; temperature conversion also needs an offset. • Interpret answers in context, including whole-object rounding, assumptions and approximation.