Exploring Some Geometric Themes · Lesson 7 of 13
Nets of Other Solids
“Connect polygon faces and unrolled curved surfaces to the nets of prisms, pyramids, cylinders, and cones.”
Describe nets of tetrahedra, triangular prisms, and square pyramids. Relate a cylinder’s rectangular net to circumference and height. Explain a cone’s sector using base radius and slant height. Recognise an octahedron, a dodecahedron, and the limitation of flat sphere nets.
Opening a box produces rectangles, but other solids produce different flat pieces. A triangular prism needs triangles as well as rectangles. A cylinder contains a curved surface that unrolls smoothly. A cone opens into a shape resembling a slice of a circular sheet.
The same test applies throughout: the pieces must have the right shape, size, and connections to close the intended surface. We will connect each flat piece to the part of the solid it becomes.
Tetrahedra and Pyramids
A regular tetrahedron has four congruent equilateral triangular faces. One net has a central equilateral triangle with one congruent triangle attached to each side. Hold the central one as the base and fold the other three upwards until their free vertices meet.
Another tetrahedron net places the four triangles in a zigzag chain. These are the two distinct net forms for a regular tetrahedron when rotations and reflections are identified. In either form there are exactly four faces, even if glue tabs are added for the model.
A square pyramid has one square base and four triangular side faces. For a symmetric model, attach congruent isosceles triangles to the four base edges. Neighbouring triangular faces must have matching joining edges so that their free sides meet correctly.
Face shape alone is not enough. If the side triangles are too shallow, their tips may fail to meet above the centre as a genuine pyramid. For example, four equilateral triangles whose side matches the base edge do form a square pyramid, whereas arbitrarily chosen triangles need to be checked.
Problem
A square base has side 6 cm. Four congruent equilateral triangles of side 6 cm are attached, one to each edge. Explain how to check the face count and edge matches.
- 1.There is one square and four triangles, giving five faces.
- 2.Every triangular base edge has length 6 cm, matching its square edge.
- 3.The free triangle sides also have length 6 cm, so neighbouring side faces can meet edge to edge.
- 4.Fold a model to check that all four tips meet at the same apex and that the triangular interiors do not overlap.
Triangular Prisms
For a right triangular prism, the two matching triangles are the end faces. Each side of a triangle corresponds to one rectangular side face. If the triangle sides are a, b, and c, and the prism length is L, the rectangles measure a by L, b by L, and c by L.
The three rectangles can form a strip. Attach one triangular end to a suitable edge on each opposite boundary of that strip. Matching the triangle’s side lengths to the rectangle widths is what allows the strip to wrap around it.
Problem
Design the face sizes for a right triangular prism with end sides 3 cm, 4 cm, 5 cm and length 8 cm.
- 1.The two ends are congruent 3–4–5 right triangles.
- 2.The three side faces are rectangles measuring 3 by 8, 4 by 8, and 5 by 8 cm.
- 3.A side strip has length 3 + 4 + 5 = 12 cm around the triangular boundary and width 8 cm along the prism.
- 4.Attach the triangular ends so corresponding edges meet. There are five faces in total: two triangles and three rectangles.
Unrolling a Cylinder
Wrap a rectangular sheet around a circular tube. One pair of opposite edges meets along a straight vertical seam. The distance once around the tube is the width of the unrolled rectangle, and the cylinder’s height becomes the rectangle’s other dimension.
If the base radius is r, the circumference is 2πr. A closed cylinder therefore needs a rectangle of dimensions 2πr by h and two circles of radius r. The rectangle width matches the whole circular boundary, not the diameter 2r.
Problem
A closed cylinder has radius 7 cm and height 10 cm. Using π = 22/7, find the required flat pieces.
- 1.Find the circumference: 2 × 22/7 × 7 = 44 cm.
- 2.The curved surface unrolls into a rectangle 44 cm by 10 cm.
- 3.Add two circles of radius 7 cm. Their diameters are 14 cm, but 14 cm is not the rectangle’s width.
- 4.A real model may need a joining tab; keep its extra width separate from the mathematical 44 cm measurement.
Unrolling a Cone
Cut a right circular cone along a straight line from its apex to its base rim. Open its curved surface without stretching it. The resulting piece is a sector of a circle: two radii and the arc between them.
The sector centre becomes the cone’s apex. Its radius is the slant height s, measured down the cone’s surface from apex to rim. This is different from vertical height h, measured straight down inside the cone. The sector arc becomes the whole base circumference, so its length is 2πr.
Problem
A right circular cone has base radius 3 cm and slant height 6 cm. What fraction of a radius-6 circle is needed?
- 1.The cone rim must have length 2π × 3 = 6π cm.
- 2.A full circle of radius 6 cm has circumference 12π cm.
- 3.The required arc is half of that full circumference, so use a semicircular sector with angle 180°.
- 4.Bring its two straight radii together and add a circular base of radius 3 cm to close the cone.
Moving a cone’s apex sideways produces an oblique cone. Distances from that apex to different rim points are generally unequal, so its opened surface does not have the same simple circular-sector description. The neat sector rule belongs to the right circular cone, whose apex lies directly above the base centre.
Octahedra, Dodecahedra, and the Sphere
Join two square pyramids base to base. The shared squares become internal and are not outside faces. The eight triangular side faces form an octahedron. A regular octahedron has eight equilateral faces, twelve edges, and six vertices. It has 11 distinct nets under the usual rotation-and-reflection convention.
A regular dodecahedron uses twelve regular pentagonal faces. The many possible cutting choices explain why it has far more nets: 43,380. You do not need to draw them all to understand the main point: one solid can have many different unfoldings.
A sphere behaves differently. You cannot flatten an exact spherical surface onto one plane without stretching, tearing, or overlapping. Thin strips and small panels can approximate a globe, but they do not provide a perfect ordinary flat net of the sphere. The smooth curve in every direction is what makes paper wrapping wrinkle.
You can make an octahedron from eight equal equilateral triangles using the net below. Six triangles form a zigzag strip; one extra triangle is attached above the strip and one below. Fold along shared sides so that four triangles meet at each vertex. The two square-pyramid halves help you imagine the result, but neither hidden joining square belongs in this eight-triangle net.
Copy the net with a convenient triangle side such as 4 cm. Keep the joining edges uncut and add any glue tabs outside the eight faces. Fold gently and check that all free boundary edges pair up, without leaving a ninth face or an opening. The two green triangles close portions of the surface that the six-triangle strip alone would leave open.
Compare Curved Surfaces
Use a paper cylinder, a paper cone, and a ball to investigate flattening. Keep the investigation about the surface shape.
- Open the cylinder along one straight seam and identify the rectangle.
- Open the cone from apex to rim and identify the sector.
- Try gently fitting a flat sheet around the ball without stretching it.
- Compare the cylinder’s and cone’s clean openings with the ball’s folds or gaps.
Cylinders and cones can be developed into flat pieces along suitable cuts. A sphere requires distortion or approximation. This is a geometric distinction, not simply a problem of choosing a larger sheet.
Quiz
Which pieces form the faces of a triangular prism?
What equals the width around a cylinder in its rectangular net?
What does the radius of a cone’s sector represent?
How many external faces remain when two square pyramids are joined base to base?
Why is a flat paper sphere model only an approximation?
Practice Problems
- Describe the faces in a regular tetrahedron net and state how many distinct net forms it has.
- A right triangular prism has end sides 5, 5, and 6 cm and length 9 cm. List its pieces.
- A cylinder has radius 3 cm and height 8 cm. Give its net dimensions using π exactly.
- A cone has radius 4 cm and slant height 12 cm. Find its sector angle.
- Explain why the joining square is not counted twice as an octahedron face.
1. It contains four congruent equilateral triangles. 2. The two net forms are a central triangle with three neighbours and a zigzag chain, up to rotation and reflection.
Key Takeaways
A net matches both face shapes and joining-edge lengths. A right triangular prism has two triangular ends and three rectangular sides. A cylinder opens into a circumference-by-height rectangle plus circular bases. A right cone opens into a sector whose radius is slant height and whose arc is base circumference. An octahedron has eight triangular faces; a dodecahedron has twelve pentagonal faces. A sphere has no exact ordinary flat net without distortion.