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Lesson 11 of 13

Exploring Some Geometric Themes · Lesson 11 of 13

Cube Arrangements from Multiple Views

“Read cube stacks, reconstruct possible models, and explain why the same views can conceal different totals.”

Learning Objectives

Draw front, top, and side profiles of a unit-cube arrangement. Use a height table to describe supported stacks precisely. Count hidden cubes by columns and layers. Check whether several different arrangements satisfy the same views.

Unit cubes make solid geometry tangible. You can build a staircase, an arch, or a letter, then ask someone else to reconstruct it from drawings. The challenge is that one view may hide cubes behind others.

We will use two descriptions together: a drawing that helps us see the solid, and a height table that records its columns exactly. This prevents a common error—counting visible squares as if every visible square were a separate cube.

A Fixed Front and a Height Table

Place cubes on a horizontal grid and choose a front direction. A height table records the number of cubes in each vertical column. In the supported-stack model, every column starts on the ground with no empty spaces below its top cube. A zero means that the ground position is empty.

In the table below, rows move from front to back and columns move from left to right. The front row has heights 2, 1, 0; the back row has heights 1, 2, 1. Keep this orientation fixed when drawing views.

Ground rowLeftMiddleRight
Front210
Back121
Seven cubesTop footprintFront heights: 2, 2, 1Side: 2, 2Top row in footprint = front ground row
An arrangement, its footprint, and two height profiles— The height table defines the orientation. The top footprint records occupied ground positions, not how many cubes sit above each one.

Reading the Three Views

For a top view of supported stacks, show one square for each occupied ground position. A stack of height 1 and a stack of height 5 both occupy one top-view square. The ordinary top silhouette therefore tells us where columns exist but not their heights.

For the front view, look along the front-to-back direction. At each left-to-right position, the tallest column in that line determines the silhouette height. Here the left heights are 2 and 1, giving front height 2; the middle heights are 1 and 2, giving 2; the right heights are 0 and 1, giving 1.

For a side view, do the same across each left-to-right row. The front row’s maximum is 2 and the back row’s maximum is 2. A side silhouette therefore has heights 2 and 2. In this lesson, side sequences are stated explicitly from front to back to avoid accidental mirroring.

Drawing views from a height table

Problem
For front row [2,1,0] and back row [1,2,1], find the footprint, front heights, side heights, and cube total.

  1. 1.There are five nonzero table entries, so the top footprint has five occupied squares.
  2. 2.Take the maximum in each column across depth: max(2,1), max(1,2), max(0,1), giving [2,2,1].
  3. 3.Take the maximum in each ground row: max(2,1,0) = 2 and max(1,2,1) = 2, giving side heights [2,2].
  4. 4.Add every stack height for the actual total: 2 + 1 + 0 + 1 + 2 + 1 = 7 cubes.
Common mistake

The front profile uses maximum heights, not sums. A height-2 column behind a height-1 column does not appear as height 3. The cubes share the same ground level, so the silhouette reaches the taller height, 2.

Reconstructing a Possible Solid

Start with the top footprint to locate allowed columns. Front and side heights then limit each column. If a front position can reach only 2 units and a side position only 1 unit, their intersecting column cannot be taller than 1 unit.

After choosing heights, check all three views again. Every specified front maximum and side maximum must actually be reached somewhere; making every column too short can satisfy the upper limits while still failing the drawings. A possible arrangement is a solution only when every given view agrees.

Two different totals with the same silhouettes

Problem
A full 2 by 2 footprint has front heights [2,2] and side heights [2,2]. Must it contain eight cubes?

  1. 1.A solid 2 by 2 by 2 block has height table [[2,2],[2,2]] and contains eight cubes.
  2. 2.Consider instead [[2,1],[1,2]]. Every ground position is occupied, so the top footprint is unchanged.
  3. 3.Every front column and every side row still reaches height 2, so both silhouettes are unchanged.
  4. 4.Its total is 2 + 1 + 1 + 2 = 6 cubes. The given silhouettes do not determine a unique total.

For this full 2 by 2 footprint, six is the minimum under the supported-stack assumption: four cubes are needed to occupy the ground positions, and two additional cubes in different rows and columns make every front and side height reach 2. Eight is the maximum because no column may exceed 2. An arrangement with seven cubes also fits.

This ambiguity concerns the stated silhouette information. A more detailed drawing with visible step edges, a height-labelled top plan, or a perspective view may distinguish the alternatives. Always use the information actually supplied.

Counting by Layers

When a mound hides cubes behind its front surface, count complete horizontal layers rather than only visible top faces. Imagine removing the top layer, then the next, while keeping track of each layer’s footprint.

A triangular stepped mound four cubes high can have bottom-layer rows of 4, 3, 2, and 1 cubes. The next layer has rows 3, 2, and 1; the next has 2 and 1; the top has 1. Count every layer, including its hidden supporting cubes.

Counting a four-level triangular mound

Problem
Find the total for the triangular mound described above.

  1. 1.Bottom layer: 4 + 3 + 2 + 1 = 10 cubes.
  2. 2.Second layer: 3 + 2 + 1 = 6 cubes. Third layer: 2 + 1 = 3 cubes.
  3. 3.Top layer: 1 cube. Total = 10 + 6 + 3 + 1 = 20 cubes.
  4. 4.The answer assumes the full supported layers specified. A hollow construction would require different information.

Letters Made from Cubes

Glued cubes can form overhangs, so not every arrangement is a ground-supported stack. For example, make a block letter C one cube thick: a left column four cubes high, a top row three cubes wide, and a bottom row three cubes wide. The shared corner cubes belong to both a row and the column but count only once.

This model uses 4 + 2 + 2 = 8 cubes. From the front it looks like C. From above, its occupied positions form a row of three squares. From the side, they form a column of four squares. Neither the top nor side silhouette reveals the central opening visible at the front.

Eight-cube letter CFrontTopSide
A letter can disappear in another view— The front C has an opening. Top and side silhouettes hide that opening; this glued model can include overhangs.

Change One View While Preserving Another

Use the eight-cube C as a starting model. Place extra cubes behind existing cubes, then predict what happens before looking.

  1. Add a cube directly behind one existing cube at the same height.
  2. Check that its front projection falls behind an already occupied front square.
  3. Look from above and from the side to identify the newly visible depth information.
  4. Try making different letter-like outlines from different directions, and explain any physical support or gluing needed.

An addition can be invisible from the front while changing the top or side. To preserve all three views at once, an added cube must project into already occupied positions in all three directions. That is why hidden-cube questions need careful checking.

Quiz

Quick check

For supported stacks, what determines a front silhouette’s height at one position?

Quick check

How many cubes are in [[2,1,0],[1,2,1]]?

Quick check

What does an unlabelled top footprint show?

Quick check

Can [[2,1],[1,2]] and [[2,2],[2,2]] have the same three silhouettes?

Quick check

How many cubes are in layers containing 10, 6, 3, and 1 cubes?

Practice Problems

Practice Problems
  1. For front row [1,3] and back row [2,1], find the front heights, side heights, footprint size, and total.
  2. Give a seven-cube arrangement with a full 2 by 2 footprint and front and side heights [2,2].
  3. Why is five cubes insufficient for that full 2 by 2 footprint and both height profiles [2,2]?
  4. Count a triangular mound with bottom rows 3,2,1; middle rows 2,1; and top row 1.
  5. For the eight-cube C, explain why adding one cube behind its upper-right cube preserves the front silhouette.

1. Front maxima are [2,3]. 2. Side maxima from front to back are [3,2]. 3. All four ground positions are occupied. 4. The total is 1 + 3 + 2 + 1 = 7 cubes.

Key Takeaways

Key Takeaways

Height tables specify supported columns and prevent hidden-cube counting errors. Front and side silhouettes use maximum heights along viewing lines. The top footprint records occupied positions, not all column heights. Different cube totals can share the same three silhouettes. Count a filled mound by complete layers or columns. Glued letter models may have overhangs and need a different assumption from supported stacks.