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Lesson 6 of 12

Constructions and Tilings · Lesson 6 of 12

Regular Hexagons

“Build a regular hexagon from equilateral triangles, exact angles, and equal compass lengths.”

Learning Objectives

• Explain what makes a polygon regular. • Use six equilateral triangles to justify a regular hexagon. • Calculate missing angles around a point. • Construct 60° and 120° angles with a compass. • Construct regular hexagons with specified side lengths.

Regular Polygons

A polygon is a closed figure made of straight sides. A regular polygon has equal side lengths and equal interior angles. An equilateral triangle is a regular three-sided polygon, and a square is a regular four-sided polygon. Equal sides alone do not make every polygon regular.

Definition
Regular hexagon

A polygon with six equal sides and six equal interior angles.

The source asks you to explore drawing pentagons and hexagons with equal sides. The exact regular-pentagon construction requires ideas developed later; we will not assume it has already been learned. A regular hexagon, however, can be built using equilateral triangles and the angle constructions available now.

A useful approach is to start with pieces we know how to construct and ask whether they form the required whole. This is stronger than drawing a six-sided figure and deciding by appearance that it must be regular.

Regular Hexagon and Equilateral Triangles

Imagine six congruent equilateral triangles with one vertex of each at a common centre O. Each triangle has three equal sides and three angles of 60°. We need to know whether six such pieces fit around O without leaving a gap or overlapping.

ABCDEFO60°6 × 60° = 360°
Six equilateral triangles form a regular hexagon— All six pieces have equal sides. Their 60° angles fill a full turn at O.

The angles around O total 6 × 60° = 360°, so the pieces exactly fill the turn. Each outer side is one side of an equal triangle, so the six outer sides match. At each outer vertex, two 60° triangle angles meet; the interior angle is 120°. Thus both requirements for regularity are satisfied.

Joining opposite vertices through O gives a straight line because three successive central angles total 3 × 60° = 180°. This explains the opposite-vertex lines in the diagram. It also shows that the distance from O to any vertex equals an outer side length: both are sides of the same equilateral pieces.

Angles Around a Point

A full turn gives a way to check whether pieces can fit at one meeting point. Their angles must add to 360° to cover that point without gaps or overlaps. A small missing angle is still a gap; an excess means some pieces would overlap.

Full turnLaTeX
Add the given angles and subtract their sum from 360° to find a remaining gap.
Example — The source gap-angle problem

Problem
The given angles are 40°, 60°, 50°, 30°, 40°, and 90°. Can a 70° angle fill the remaining gap?

  1. 1.Add the known angles in stages: 40° + 60° = 100°, then +50° = 150°, +30° = 180°, +40° = 220°, and +90° = 310°.
  2. 2.The remaining angle is 360° − 310° = 50°.
  3. 3.A 70° angle is 20° larger than the available gap. It would overlap a neighbouring piece, so it does not fit.
  4. 4.The reason comes from the full turn, not from the apparent shape of the drawing.
40°60°50°30°40°90°50°Known angles: 310°Remaining gap: 50°70° is 20° too large
The gap is 50°, not 70°— The six given sectors total 310°. The orange remaining sector completes the full 360° turn.

Construction of a 60° Angle

An equilateral triangle supplies an exact 60° angle. We can produce that triangle using equal compass distances. This method turns a length equality into the angle we need.

  1. Start with ray AX. With centre A and a chosen radius, mark B on the ray.
  2. With the same radius and centre B, draw an arc meeting the first circle or arc at C on the chosen side.
  3. Draw AC. AB, BC, and CA are all equal to the compass radius.
  4. Triangle ABC is equilateral, so ∠CAB = ∠CAX = 60°.
ABXStep 1ABXC60°Step 2AB = AC = BC → equilateral triangle → 60°
Two stages for constructing 60°— The first arc locates B. The equal-radius arc from B locates C, completing an equilateral triangle.

The adjacent angle on the straight line is 180° − 60° = 120°. You can therefore obtain the interior angle needed for a regular hexagon from the same construction. Keep track of which ray gives 60° and which straight-line continuation gives its 120° neighbour.

Example — Construct the basic hexagon angles

Problem
Construct an angle of 60° and then an adjacent angle of 120°.

  1. 1.Use equal-radius arcs from A and B to obtain C, giving an equilateral triangle ABC.
  2. 2.The angle between AB and AC is 60°.
  3. 3.Extend BA beyond A to a point D. Rays AB and AD are opposite directions on one straight line.
  4. 4.Therefore ∠DAC = 180° − 60° = 120°. The same ray AC forms the two supplementary angles with the opposite base rays.

Constructing a Regular Hexagon

The six-triangle view provides a direct compass construction. Because the radius from the centre to a vertex equals the side length, the same compass opening can draw the circle and step around its circumference. Each step builds another equilateral triangle.

  1. Choose the required side length s and draw a circle with centre O and radius s.
  2. Mark one point A on the circle. Keep the compass opening equal to s.
  3. From A, mark the next circle point B. Continue in the same direction to C, D, E, and F.
  4. The next step returns to A because six 60° central angles make 360°. Join consecutive vertices to obtain the hexagon.
  5. Keep the circle and centre visible until you have checked the six equal sides and triangle arrangement.
Example — A regular hexagon of side 4 cm

Problem
Construct a regular hexagon with each side 4 cm.

  1. 1.Draw a circle of radius 4 cm and mark A on it.
  2. 2.Keeping the 4 cm opening, step around to obtain B, C, D, E, and F, always choosing the next point in the same direction.
  3. 3.Join AB, BC, CD, DE, EF, and FA. Each chord is 4 cm by construction.
  4. 4.Each central triangle has all three sides 4 cm. Its centre angle is 60°, so six steps close the figure and every interior angle is 120°.
Example — A regular hexagon of side 5 cm

Problem
Construct the source’s second hexagon, with side length 5 cm, using successive sides and 120° angles.

  1. 1.Draw the first side 5 cm long. Construct the required 120° interior angle at its endpoint and transfer 5 cm onto the new direction.
  2. 2.Repeat the same interior angle and side length as you proceed around the figure, always turning consistently toward the interior.
  3. 3.Construct six sides in total and check that the last endpoint meets the first. The repeated sides can also be understood as the outer sides of six equilateral triangles.
  4. 4.A small failure to close indicates practical drawing error. Do not silently change the last side length to hide it.
Common mistake

A six-sided figure with equal-looking edges is not necessarily a regular hexagon. Verify equal side lengths and equal interior angles. Also, keep the compass opening unchanged when stepping around the circle; changing it removes the equilateral-triangle reasoning.

Check Your Understanding

Use these questions to check the conditions behind each method, as well as the result. For a diagram-based question, follow the labels and given information rather than judging by appearance.

Quiz

Quick check

What must be equal in a regular polygon?

Quick check

What is the interior angle of a regular hexagon built from equilateral triangles?

Quick check

Why do six equilateral triangle angles fit around the centre?

Quick check

The known angles around a point sum to 270°. What is the gap?

Quick check

For this regular-hexagon construction, how does the circle radius compare with the side length?

Practice Problems

Practice Problems
  1. Construct a regular hexagon with side 4 cm and show its six central triangles.
  2. Construct a second regular hexagon with side 5 cm using a 120° interior-angle method.
  3. Explain why an opposite-vertex line through the centre is straight.
  4. Five angles around a point are 50°, 70°, 60°, 80°, and 40°. Find the remaining angle.
  5. In a regular hexagon of side 3 cm, find the centre-to-vertex distance and justify it.
  6. Explain why equal sides alone are insufficient to call an arbitrary polygon regular.

Use a radius-4 cm circle and unchanged opening for all six chords. The triangles are equilateral and the central angles are 60°.

Key Takeaways

Key Takeaways

• A regular polygon has equal sides and equal interior angles. • Six congruent equilateral triangles fit because their central angles total 360°. • A regular hexagon has 120° interior angles. • Equal-radius arcs construct 60° through an equilateral triangle. • The adjacent straight-line angle gives 120°. • A regular hexagon can be stepped around a circle whose radius equals its side length.