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Lesson 7 of 10

The Other Side of Zero · Lesson 7 of 10

Integers in Money, Height, Time, and Temperature

“Choose a reference point and interpret signed numbers in everyday measurements and records.”

Learning Objectives

• Represent credits, debits, and account balances with signed numbers. • Read heights and depths relative to sea level. • Interpret Celsius temperatures above and below zero. • Compare signed measurements and find changes. • Count years across BCE and CE without inserting a year zero. • Explain why a sign depends on the chosen reference and meaning.

A balance records a running total

Money coming into an account increases its balance; money leaving decreases it. We can represent incoming amounts, called credits, by positive numbers and outgoing amounts, called debits, by negative numbers. Adding the changes to the previous balance gives the new balance.

A negative balance has a meaning: more has been taken out than was available. It is not a negative number of coins in someone’s hand. Some accounts allow a temporary negative balance under agreed conditions, and fees or interest may apply. Here we use a simplified record to learn the arithmetic; real account rules need to be checked separately.

Definition
Credit and debit

A credit adds money to an account. A debit removes money from it. In our signed record, credits are positive changes and debits are negative changes.

Example — Following an account through zero

Problem
Start with ₹100, then credit ₹60, debit ₹30, debit ₹150, and finally credit ₹200. Find the balance after each change.

  1. 1.₹100 + ₹60 = ₹160 after the first credit.
  2. 2.₹160 + (−₹30) = ₹130 after the first debit.
  3. 3.₹130 + (−₹150) = −₹20 after the larger debit: the account is ₹20 below zero.
  4. 4.−₹20 + ₹200 = ₹180 after the last credit. The first ₹20 cancels the negative balance, leaving ₹180.
StageChangeNew balance
Opening amount+₹100₹100
Credit+₹60₹160
Debit−₹30₹130
Debit−₹150−₹20
Credit+₹200₹180

The balance and the latest change are different quantities. A ₹200 credit does not necessarily produce a ₹200 balance because the account already had a value. You can also combine all the changes first, then add that total to the opening balance. Both methods keep track of the same money.

Example — Combining credits and debits

Problem
An account starts at zero, has credits ₹30, ₹40, ₹50 and debits ₹40, ₹50, ₹60. Find its balance.

  1. 1.Total credits are 30 + 40 + 50 = ₹120.
  2. 2.Total debits remove 40 + 50 + 60 = ₹150.
  3. 3.The balance is 120 + (−150) = −₹30. Equivalently, matching ₹40 and ₹50 credits with equal debits leaves ₹30 − ₹60.
Example — Doubling debits

Problem
Starting at zero, debit ₹1, ₹2, ₹4, ₹8, ₹16, ₹32, ₹64, ₹128, then credit ₹256. What remains?

  1. 1.Combine the debit sizes in stages: 1 + 2 = 3; +4 gives 7; +8 gives 15; +16 gives 31.
  2. 2.Continuing gives 63, 127, and finally 255. Thus the combined debit is −₹255.
  3. 3.Adding the credit gives −255 + 256 = +1, so the balance is ₹1.

An account owner might accept a temporary negative balance to complete a planned purchase, but must consider repayment and any charges. Discuss the meaning of the negative total without assuming that every bank permits it. The arithmetic shows the balance; it does not by itself decide whether a purchase is sensible.

Sea level is a geographical zero

A mountain’s height is measured relative to sea level rather than the ground directly beneath your feet. Sea level is assigned 0 m. A point above that reference has positive height, while a point below it has negative height. A geographical cross-section is a side view of an imagined vertical slice through the landscape.

In the cross-section below, the vertical scale measures metres relative to sea level. Point A is the highest and D is the lowest. The values are approximate readings: a smooth landscape drawing is not a measuring instrument accurate to a single metre. Heights between labelled scale values should be described with suitable care.

−1500−1000−500050010001500ABCDEFGSea level = 0 mApproximate height relative to sea level (m)
A geographical cross-section— Order points by vertical height. Sea level is zero even when the drawing shows both land and water.
PointApproximate height
A+1500 m
B−500 m
C+300 m
D−1200 m
E+1200 m
F−200 m
G+100 m
Example — Ordering heights

Problem
Arrange points A–G from lowest to highest and find the upward change from B to E.

  1. 1.The negative heights come first: D at −1200, B at −500, then F at −200.
  2. 2.The remaining points are G at +100, C at +300, E at +1200, A at +1500.
  3. 3.From B to E, use target minus start: 1200 − (−500) = 1700 m upward. These calculations use the approximate readings above.

To extend the investigation, locate the highest point above sea level and a very deep point on the ocean floor in an atlas. Record the unit and reference level along with the measurement. Different surveys can report slightly different heights or depths, so precision should match the information available.

Below zero can also mean colder

A Celsius thermometer is another vertical number line. Its 0°C reference corresponds to the freezing point of water under ordinary conditions. Temperatures above 0°C are positive, and those below 0°C are negative. Below zero does not mean that there is no heat or that a temperature is impossible.

A thermometer showing 40°C is warmer than one showing 15°C. A reading of −4°C is colder than −2°C because −4 is lower on the scale. The difference from −4°C to +14°C is an increase of 18°C: four degrees to reach zero and fourteen degrees farther.

−5051015202530−4°C−5051015202530+14°C
Temperatures on both sides of zero— The same scale is used for both thermometers. The higher red level represents the warmer temperature.
Example — Matching a sample day in Leh

Problem
Match −4°C, −2°C, 8°C, and 14°C to 2 a.m., 11 a.m., 2 p.m., and 11 p.m. using a plausible daily warming and cooling pattern.

  1. 1.The coldest time is usually late at night or before dawn, so match −4°C with 2 a.m.
  2. 2.The afternoon is usually warmer than late morning: match 14°C with 2 p.m. and 8°C with 11 a.m.
  3. 3.Match −2°C with 11 p.m. This is a reasonable interpretation for the sample day, not a rule for every day or place.

You can investigate summer and winter temperatures in your own area, or places in India that sometimes fall below 0°C. Discuss why high elevations and winter conditions can produce colder readings. When using a thermometer to compare warm and cool water, follow an adult’s guidance and avoid hot water that could burn you.

Years need an extra convention

An ordinary integer line includes zero, but traditional BCE/CE calendar labels do not include a year 0. The sequence is 3 BCE, 2 BCE, 1 BCE, 1 CE, 2 CE, 3 CE. Use this sequence when counting elapsed years across the boundary; do not insert an extra calendar year.

Example — Moving forward within BCE

Problem
What year is 320 years after 680 BCE?

  1. 1.BCE year labels decrease as time moves forward towards 1 BCE.
  2. 2.This journey stays in BCE, since 320 is less than the years needed to reach the boundary.
  3. 3.680 − 320 = 360, so the answer is 360 BCE. Write the era label, without an extra minus sign.
Example — Counting across the boundary

Problem
Using 2026 CE as a fixed reference, what year was 2200 years earlier?

  1. 1.From 2026 CE back to 1 CE is 2025 years.
  2. 2.One more year reaches 1 BCE, for a total of 2026 years.
  3. 3.There are 2200 − 2026 = 174 years left. Counting back 174 years from 1 BCE gives 175 BCE. Check: 175 + 2026 − 1 = 2200 elapsed years.
A reference zero is not the same in every context

0 m is sea level, 0°C is a temperature reference, and a ₹0 balance means no net money in our record. BCE/CE calendar naming has no year 0. Do not transfer one context’s convention without checking its meaning.

Quiz

Quick check

A balance of −₹20 receives a ₹200 credit. What is the new balance?

Quick check

Which point is lowest?

Quick check

What is the increase from −4°C to 14°C?

Quick check

Which is colder?

Quick check

Which year follows 1 BCE?

Quick check

What year is 320 years after 680 BCE?

Practice Problems

Practice Problems
  1. Starting from ₹0, credit ₹70 and debit ₹90. Then credit ₹35. Find each balance.
  2. Repeat the credits ₹30, ₹40, ₹50 and debits ₹40, ₹50, ₹60 calculation by cancelling matching amounts.
  3. Explain why the doubling debits followed by a ₹256 credit leave ₹1.
  4. Arrange A–G from highest to lowest using the cross-section.
  5. Find the signed change from E at +1200 m to D at −1200 m.
  6. A temperature changes from −2°C to +8°C, then to −4°C. Find each change.
  7. Using 2026 CE as the reference year, find the year 150 years earlier and 2200 years earlier.
  8. How many years elapse from 3 BCE to 3 CE? Write the intervening year labels.
  9. Research a highest point above sea level and a deep ocean point using an atlas. Explain the signs in your measurements.

₹70, −₹20, then ₹15.

Key Takeaways

Key Takeaways

• A credit is a positive change and a debit is a negative change in our account model. • The total balance depends on previous balances as well as new changes. • Sea level and 0°C are reference values for signed measurements. • Target minus start finds a change in height or temperature. • Traditional BCE/CE year labels pass directly from 1 BCE to 1 CE. • Interpret a sign only after identifying the context and reference.