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Lesson 11 of 12

Structure of Atom · Lesson 11 of 12

Writing Electronic Configurations

“Build electron arrangements, identify ions, and understand important configuration exceptions.”

Learning Objectives

• Write full configurations, noble-gas shorthand, and orbital diagrams. • Identify core and valence electrons and count unpaired electrons. • Apply electron counting to main-group ions and isoelectronic species. • Explain chromium and copper configurations using total-energy considerations. • Relate symmetry and exchange stabilisation to half-filled and filled subshells.

From filling rules to a complete configuration

An electronic configuration specifies how electrons are distributed among atomic orbitals. Begin with the electron count, then apply the energy order, Pauli exclusion, and Hund’s rule. The sum of every occupation number must equal the species’ total electron count. Checking that sum is an essential final step.

In subshell notation, a leading number gives n, a letter gives the subshell type, and a superscript gives its electron occupation. Thus means four electrons distributed among three 2p spatial orbitals, not four p orbitals. An orbital-box diagram gives additional information by showing individual orbitals and spin arrows.

The order in which subshell terms are written is not itself an electron transition. For example, writing occupied 3d before 4s is a common configuration convention even when the simple building-up sequence placed 4s first. What matters is the occupation assigned to each subshell.

Building the first two periods

Hydrogen has one electron in 1s. Helium adds a second electron with opposite spin in the same spatial orbital, filling 1s. Lithium’s third electron cannot enter an already full 1s orbital, so it occupies 2s. Beryllium completes 2s; the next six electrons progressively fill 2p from boron through neon.

Carbon’s two p electrons occupy different p orbitals with parallel spins. Nitrogen’s three occupy all three p orbitals singly. Oxygen’s fourth p electron begins pairing, followed by further pairing in fluorine and neon. These examples show why an electron count alone is not enough to draw a correct spin diagram.

AtomConfiguration2p orbital patternUnpaired electrons
B↑ | empty | empty1
C↑ | ↑ | empty2
N↑ | ↑ | ↑3
O↑↓ | ↑ | ↑2
F↑↓ | ↑↓ | ↑1
Ne↑↓ | ↑↓ | ↑↓0
Example — Writing oxygen’s configuration

Problem
Write the ground-state configuration and count unpaired electrons for oxygen, Z = 8.

  1. 1.Fill 1s and 2s with two electrons each. Four remain, giving . The occupations sum to 8.
  2. 2.Place one up-spin electron in each p orbital, then add the fourth with opposite spin to one of them.
  3. 3.One p orbital is paired and two are singly occupied. Oxygen has two unpaired electrons in this ground-state orbital description.

Noble-gas shorthand and periodic patterns

A bracketed noble-gas symbol replaces an already completed core configuration. For sodium, [Ne] represents ten electrons, leaving one electron in 3s. From sodium through argon, the 3s and 3p pattern repeats the 2s and 2p pattern from lithium through neon.

For main-group elements, the occupied shell with the largest n contains the familiar valence electrons involved in bonding and reactions. The remaining filled inner electrons form the core. Transition-metal chemistry can also involve electrons in the incompletely filled d subshell, so “valence” should not be reduced to a universal highest-n-only rule.

Potassium and calcium begin filling 4s. Scandium through zinc progressively occupy 3d, followed by 4p from gallium to krypton. Rubidium through xenon similarly involve 5s, 4d, and 5p. Later rows introduce 4f and then 5f occupation. The longer reference table shows the pattern and its exceptions; it is a lookup aid rather than a demand to memorise every row.

Example — Using a core abbreviation

Problem
Write phosphorus, Z = 15, in full and shorthand form, and count its unpaired electrons.

  1. 1.Fifteen electrons give . The first ten match neon.
  2. 2.The shorthand is . It contains five outer-shell electrons: two in 3s and three in 3p.
  3. 3.The three p electrons occupy different orbitals with parallel spins. Therefore phosphorus has three unpaired electrons.

Ions and isoelectronic species

For an ion, adjust the electron count before building or checking its configuration. An anion has gained electrons; a cation has lost them. The nucleus still identifies the element. Main-group ions often reach the same electron count and configuration as a nearby noble gas.

Isoelectronic species have the same number of electrons. This does not make them the same element or guarantee equal size and energy, because their nuclear charges can differ. Count electrons explicitly rather than comparing only the symbols or charge magnitudes.

Example — A set of ten-electron species

Problem
Write configurations for , , and .

  1. 1.Sodium has electrons; oxygen has ; fluorine has .
  2. 2.Each has configuration , the neon configuration.
  3. 3.They are isoelectronic but have different proton numbers. Equal electron counts do not cancel the difference in nuclear attraction.
Example — Identifying an atom from a configuration

Problem
A neutral atom has configuration . Identify it.

  1. 1.Argon represents 18 electrons. The explicitly written subshells add three.
  2. 2.There are 21 electrons. Neutrality means Z = 21, identifying scandium.
  3. 3.If the species were an ion, the same electron count would not alone fix the element without knowing its charge.

Why chromium and copper are exceptions

The simple sequence predicts chromium as an argon core followed by four 3d electrons and two 4s electrons. Its observed ground state instead has five 3d electrons and one 4s electron. Copper similarly has ten 3d electrons and one 4s electron rather than nine and two.

The 3d and 4s arrangements are close in energy. Redistributing occupation can lower the total energy after attractions, repulsions, and exchange effects are included. Half-filled and filled subshells often receive extra stabilisation, helping explain these examples. This is a comparison of entire configurations, not a claim that an electron moves upwards in energy and the total energy must therefore rise.

AtomSimple sequence predictionObserved ground-state arrangement
Cr
Cu

Symmetry and exchange stabilisation

A half-filled or filled set of degenerate orbitals distributes electrons symmetrically across the available angular states. Different orbitals in a subshell have different spatial distributions, so their electrons need not overlap in the same way as a forced pair in one orbital. The balance of Coulomb repulsion and nuclear attraction can favour these arrangements.

Parallel-spin electrons also produce exchange stabilisation, a quantum effect related to the allowed combined electron wave function. Introductory diagrams often show pairs of parallel-spin electrons exchanging labels. These are a way to count exchange pairs, not a movie of distinguishable electrons swapping positions and emitting energy on each swap.

For five singly occupied d orbitals with parallel spins, there are distinct pairs. For a filled d subshell there are two groups of five same-spin electrons, giving 20 such pairs in this simple counting picture. These counts help illustrate Hund’s rule but do not calculate actual configuration energies by themselves. Other exceptions exist, and the slogan “half-filled is stable” cannot predict every element.

↑1↑2↑3↑4↑5Five singly occupied d orbitalsArcs show pair counting, not literal electron trajectories.
Counting exchange pairs in a half-filled d subshell— With five parallel-spin electrons, pairing each label with the later labels counts 4 + 3 + 2 + 1 = 10 distinct pairs.
Example — Unpaired electrons in chromium and iron

Problem
Compare ground-state unpaired electrons in chromium and iron.

  1. 1.Chromium is : five unpaired d electrons plus one unpaired s electron give six.
  2. 2.Iron is . The sixth d electron pairs in one of five d orbitals, leaving four d electrons unpaired; 4s is paired.
  3. 3.Therefore chromium has six and iron four unpaired electrons in these isolated-atom ground-state configurations. Count every occupied subshell, not only d.

Reference configurations and chemical meaning

The reference below expresses the long configuration table compactly using noble-gas cores. Each row should be read as an occupation pattern whose electron count equals Z. The ordinary building-up sequence is a guide; rows such as niobium, palladium, platinum, and gold show why exceptions cannot all be reduced to one slogan.

Electronic arrangement helps explain why elements with closed outer shells are comparatively unreactive, why many other elements readily form bonds, and why different elements show different chemical behaviour. Detailed bonding and periodic trends are developed later; the purpose here is to establish the electron arrangement needed to understand them.

ElementZConfiguration
H1
He2
Li3
Be4
B5
C6
N7
O8
F9
Ne10
Na11
Mg12
Al13
Si14
P15
S16
Cl17
Ar18
K19
Ca20
Sc21
Ti22
V23
Cr24
Mn25
Fe26
Co27
Ni28
Cu29
Zn30
Ga31
Ge32
As33
Se34
Br35
Kr36
ElementZConfiguration
Rb37
Sr38
Y39
Zr40
Nb41
Mo42
Tc43
Ru44
Rh45
Pd46
Ag47
Cd48
In49
Sn50
Sb51
Te52
I53
Xe54
Cs55
Ba56
La57
Ce58
Pr59
Nd60
Pm61
Sm62
Eu63
Gd64
Tb65
Dy66
Ho67
Er68
Tm69
Yb70
Lu71
Hf72
Ta73
W74
Re75
Os76
Ir77
Pt78
Au79
Hg80
Tl81
Pb82
Bi83
Po84
At85
Rn86
ElementZConfiguration
Fr87
Ra88
Ac89
Th90
Pa91
U92
Np93
Pu94
Am95
Cm96
Bk97
Cf98
Es99
Fm100
Md101
No102
Lr103
Rf104
Db105
Sg106
Bh107
Hs108
Mt109
Ds110
Rg111
Common mistake

The filling sequence is a useful starting prediction, not a universal exact energy ordering. Do not force chromium and copper into the naive pattern, and do not assume every configuration exception follows only from a half-filled or filled subshell. Configurations of very heavy atoms require additional care beyond this elementary model.

Quiz

Quick check

How many unpaired electrons are in a ground-state p-four arrangement?

Quick check

Which is the observed ground-state configuration of chromium?

Quick check

Which pair is isoelectronic?

Quick check

In a noble-gas shorthand, [Ne] represents:

Quick check

What is the most accurate elementary interpretation of exchange diagrams?

Practice Problems

Practice Problems
  1. Write full and shorthand configurations for silicon, sulphur, potassium, calcium, and zinc.
  2. Write configurations for , , , and .
  3. Group into isoelectronic sets.
  4. Find unpaired electrons in phosphorus, silicon, chromium, iron, and krypton.
  5. Use the reference table to identify two exceptions other than chromium and copper. Explain why a simple filling mnemonic needs exceptions.
  6. Explain qualitatively how a configuration with a different 3d/4s distribution can have lower total energy.

Key Takeaways

Key Takeaways

A configuration records subshell occupations; an orbital diagram additionally shows individual orbitals and spins. Noble-gas shorthand abbreviates a core without changing electron count. Isoelectronic species share electron count but can have different nuclear charges and properties. Chromium and copper show that total-energy balance can favour a different occupation from the simple sequence. Symmetry and quantum exchange help explain stabilisation, but no single shortcut predicts every exception.