Structure of Atom · Lesson 4 of 12
Quantised Light and the Photoelectric Effect
“Explain energy packets, black-body observations, and the ejection of electrons by light.”
• Explain why black-body radiation motivated Planck’s quantum hypothesis. • Calculate photon energy, molar photon energy, and photon emission rate. • Connect threshold frequency and work function with photoelectric observations. • Distinguish the effects of changing light intensity and changing frequency. • Explain why both wave and particle descriptions of radiation are needed.
When a wave description is not enough
Wave behaviour explains phenomena such as interference and diffraction. Interference is the superposition of waves, producing reinforcement in some places and cancellation in others. Diffraction is the spreading or bending associated with waves passing an opening or obstacle. These observations firmly establish a wave aspect of light.
However, classical nineteenth-century physics could not account satisfactorily for several measured results: the distribution of radiation from hot bodies, photoelectric emission, the temperature dependence of the heat capacity of solids, and atomic line spectra. Rather than discard observations, scientists needed a new rule for how matter exchanges energy with radiation. We develop that rule here and use it for spectra in the next lesson.
Hot objects and the black-body pattern
A heated object emits radiation over a range of wavelengths. At modest temperatures much of it is infrared. As the temperature rises, visible emission becomes noticeable, first red and then with increasing shorter-wavelength contributions. An ordinary surface can reflect, absorb, and transmit different fractions of incident radiation, making its behaviour depend on its material.
A black body is an ideal perfect absorber of incident radiation at every frequency. At a given temperature its emitted spectrum is determined by temperature, rather than the identity of a surface material. A small hole leading into an otherwise closed cavity is a useful approximation: radiation entering the hole undergoes repeated internal reflections and is very likely absorbed.
Perfect absorption at all frequencies does not mean equal emission intensity at all wavelengths. At each temperature the emitted intensity rises to a maximum and then falls. Raising temperature increases emission and shifts the peak towards shorter wavelength. Any successful theory has to explain the whole curve and its temperature dependence.
Planck’s discrete energy exchange
Planck proposed that the oscillators associated with matter emit and absorb energy in definite packets. For radiation of frequency , the smallest packet is a quantum of energy . The allowed exchanges are whole-number multiples of this amount. A staircase is a useful analogy: a person can stand on a step, not on a height halfway between adjacent steps.
The step size is not universal for every frequency. Higher-frequency radiation has a larger energy quantum. This is why the quantum idea concerns both discreteness and the relationship between energy and frequency. In describing light as particles, we call its energy packets photons.
For a collection of photons at one frequency, multiply the single-photon energy by their number. One mole contains photons, so its energy is . Power is energy per second. If all the power leaves as monochromatic radiation, dividing by the energy per photon gives the number emitted per second.
Problem
Find the energy of one mole of photons with frequency .
- 1.One photon carries .
- 2.One mole carries .
- 3.This is approximately . The large molar value comes from the enormous number of individually tiny photon energies.
Problem
An idealised source emits 100 W entirely as 400 nm light. How many photons leave each second?
- 1.Convert . Each photon carries .
- 2.The source emits each second, so .
- 3.The assumption matters: an actual bulb’s electrical rating is not necessarily the power emitted at one wavelength.
What the photoelectric experiment reveals
When sufficiently high-frequency light strikes a suitable clean metal surface, electrons are emitted. Three observations require explanation. Emission begins without a measurable classical waiting time; below a characteristic threshold frequency no electrons emerge even under very intense illumination; above threshold, increasing frequency increases the maximum kinetic energy of the emitted electrons.
Above threshold, increasing intensity at a fixed frequency increases the number of electrons emitted, provided comparable experimental conditions are maintained. It does not increase the maximum kinetic energy of each emitted electron. For potassium, for example, very bright red light may fail while weak yellow light succeeds because the relevant difference is photon energy, not simply brightness.
Einstein explained these results by treating the light–electron interaction as the transfer of one photon’s energy to one electron. A minimum energy is needed to free the electron from the metal. Any remaining energy appears as the electron’s kinetic energy. Many electrons can be emitted because a beam contains many photons, not because one photon repeatedly supplies its full energy to many electrons.
The energy balance can now be written precisely. The largest emitted kinetic energy equals the incident photon energy minus the work function; the equivalent threshold-frequency form makes the surplus frequency explicit.
| Metal | Approximate work function / eV |
|---|---|
| Lithium | 2.42 |
| Sodium | 2.30 |
| Potassium | 2.25 |
| Magnesium | 3.70 |
| Copper | 4.80 |
| Silver | 4.30 |
An electronvolt, , is an energy unit: . Do not confuse it with a volt, which measures electric potential difference. If work function and photon energy are initially in electronvolts, they can be subtracted in that unit; convert the resulting kinetic energy to joules before using SI mass to find speed.
Problem
Light of wavelength 300 nm ejects electrons from sodium with kinetic energy . Find the work function and threshold wavelength.
- 1.One photon carries . One mole carries approximately .
- 2.Subtract the molar kinetic energy: .
- 3.Per electron, .
- 4.Then . The escaping electron’s energy and the work function must refer to the same number of particles before subtraction.
Problem
A metal has threshold frequency . Find the maximum kinetic energy for incident frequency .
- 1.The photon frequency exceeds threshold, so emission is possible. The excess frequency is .
- 2..
- 3.If the light intensity is doubled without changing frequency, the maximum kinetic energy remains this value; the possible emission rate increases.
Keeping both aspects of radiation
Interference and diffraction demand a wave account; the photon account explains discrete exchanges such as the photoelectric effect. We therefore describe radiation as having wave–particle duality. The useful description depends on the experiment, but light is one physical phenomenon, not two unrelated substances.
A photon is not a tiny classical metal ball. In particular, it has zero rest mass while carrying energy and momentum. These facts prepare us for the surprising result that particles of matter, including electrons, also show wave behaviour.
A below-threshold beam cannot eject electrons by simply being made brighter in the ordinary single-photon photoelectric model used here. Greater intensity at fixed frequency means more photons arriving, while greater frequency means more energy per photon.
Quiz
At a fixed frequency, doubling the energy in a light pulse doubles what?
Which radiation carries the greatest energy per photon?
For a metal illuminated exactly at its threshold, the maximum photoelectron kinetic energy is:
Which black-body statement is correct?
Why is photoelectric emission prompt above threshold?
Practice Problems
- Find the energy of a photon of frequency .
- How many 400 nm photons carry a total of 1.0 J?
- An ideal source radiates 25 W entirely at . Find its photon emission rate.
- A metal has work function 2.13 eV. For 400 nm light, calculate photon energy, maximum kinetic energy, and maximum electron speed.
- Zero-speed photoelectrons just appear for a wavelength of . Find the threshold frequency and work function.
- Explain why weak light can eject electrons when a brighter beam at a different frequency fails.
- Sketch two qualitative black-body curves and explain what changes with temperature.
Key Takeaways
Planck’s quantum idea makes energy exchange discrete for a given radiation frequency. Photon energy increases with frequency and decreases with wavelength. The work function is the minimum energy required for photoelectric escape. Above threshold, intensity chiefly changes photon and electron numbers, while frequency changes maximum photoelectron kinetic energy. Wave and particle descriptions are both needed to account for radiation experiments.