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Lesson 3 of 10

Classification of Elements and Periodicity in Properties · Lesson 3 of 10

How Electron Configurations Build Periods and Groups

“Explain the shape of the table by following electrons into shells and subshells.”

Learning Objectives

• Connect an element’s position with its electron configuration. • Explain period lengths using orbital numbers and electron capacities. • Follow the subshell-filling sequences through the seven periods. • Explain the similar chemical behaviour of elements within a group. • Infer main-group periods and groups from outer configurations.

The arrangement of electrons explains the arrangement of elements

Atomic number tells us how many electrons a neutral atom contains. Chemistry depends strongly on how those electrons are arranged, especially the outer electrons that interact with other atoms. As electrons fill a recurring sequence of shells and subshells, similar outer arrangements appear again. That is the microscopic reason for periodicity.

Definition
Electronic configuration

The distribution of an atom’s electrons among its orbitals. A shell is labelled by the principal quantum number ; the subshells within shells are labelled s, p, d, and f.

An orbital is a permitted electron state, not a little circular path. Each orbital can contain at most two electrons. An s subshell has one orbital, p has three, d has five, and f has seven. Therefore their capacities are 2, 6, 10, and 14 electrons respectively. These numbers explain the widths of the periodic-table blocks.

SubshellAzimuthal quantum numberNumber of orbitalsMaximum electrons
s12
p36
d510
f714

The allowed values of in a shell run from 0 to . However, a period does not simply fill every subshell with the same . Subshell energies overlap: 4s begins filling before 3d, and 6s before 4f. Use the filling sequence as well as the shell labels.

Building the periods

The first period starts with the lowest-energy 1s orbital. Hydrogen contributes one electron and helium completes the 1s pair. The next element must begin a new shell, giving lithium the configuration . That new start begins the second period.

PeriodMain filling sequenceElectron capacity of that sequence
11s2
22s, 2p2 + 6 = 8
33s, 3p2 + 6 = 8
44s, 3d, 4p2 + 10 + 6 = 18
55s, 4d, 5p2 + 10 + 6 = 18
66s, 4f, 5d, 6p2 + 14 + 10 + 6 = 32
77s, 5f, 6d, 7p2 + 14 + 10 + 6 = 32

The third period has eight elements even though a 3d subshell is allowed by the quantum numbers. The 3d subshell is not filled at that stage in the sequence. After argon, potassium and calcium begin 4s filling; the 3d series then appears before the period finishes by filling 4p. Scandium begins the 3d series with a configuration commonly written , and zinc has .

A period follows a filling sequence, not one shell alonePeriod 33s2 e3p6 ePeriod 44s2 e3d10 e4p6 ePeriod 66s2 e4f14 e5d10 e6p6 e
Why period lengths change— Box widths represent electron capacities. The 3d and 4f subshells make later periods longer.

The fifth period repeats the s–d–p pattern using 5s, 4d, and 5p. The sixth and seventh add f-subshell filling. In the layout used here, the fourteen detached entries Ce–Lu and Th–Lr fit into those longer rows. Actual d- and f-element ground states can depart from a simple filling prediction because subshell energies are close; the sequence explains the overall architecture.

Example — Why the fifth period has eighteen elements

Problem
Justify the number of elements in period 5 using orbitals.

  1. 1.The relevant filling sequence is 5s, then 4d, then 5p. It is not 5s, 5p, 5d, and 5f.
  2. 2.Those subshells contain 1, 5, and 3 orbitals respectively, giving orbitals.
  3. 3.Each orbital can hold two electrons, so the capacity is electrons.
  4. 4.Adding one electron for each increase in atomic number gives eighteen positions from Rb to Xe.
Example — Why the sixth period has thirty-two elements

Problem
Explain the longer sixth period without memorising its length.

  1. 1.Its filling sequence includes 6s, 4f, 5d, and 6p.
  2. 2.The orbital counts are 1, 7, 5, and 3, giving .
  3. 3.Two electrons per orbital give .
  4. 4.The f subshell contributes fourteen additional positions compared with the s–d–p pattern of period 5.
Common mistake

The shell capacity is not a formula for the length of period . A period involves a particular energy-order sequence that can include subshells from more than one shell.

Why groups behave like families

Once a period reaches a closed outer arrangement, the next period starts a similar outer pattern at a greater distance from the nucleus. Lithium, sodium, and potassium all have one electron in an outer s subshell. Their full configurations differ, but the shared outer pattern helps explain their common tendency to form singly positive ions.

ElementAtomic numberCondensed configuration
Li3
Na11
K19
Rb37
Cs55
Fr87

The noble-gas symbol in square brackets represents the filled inner core. Thus means the neon electron arrangement plus one electron in 3s. Members of Group 1 share the general outer configuration . Their chemistry is related, but their sizes and ease of electron removal change down the group, so related behaviour does not mean identical reactivity.

For main-group elements, the largest occupied principal quantum number normally gives the period. An outer configuration identifies Group 1 and identifies Group 2, apart from helium’s special position. Configurations through identify Groups 13 through 18. For these p-block elements, add 10 to the number of outer s and p electrons to obtain the group number.

Example — Reading a main-group configuration

Problem
An atom has configuration . Locate it and explain the group.

  1. 1.The outer shell has , so the atom belongs to period 3.
  2. 2.The outer s and p subshells contain electrons.
  3. 3.A p-block atom with six outer electrons belongs to Group .
  4. 4.Counting electrons gives , so the atom is sulphur. It resembles other Group 16 elements because their outer pattern is .
Example — Reading a transition configuration

Problem
Locate an atom with outer pattern when .

  1. 1.Substitution gives , so this is in the period-4 d region.
  2. 2.For this ordinary d-block pattern, add d and s electrons: , giving Group 4.
  3. 3.With an argon core the total electron count is , identifying titanium.
  4. 4.The group rule is different from the p-block rule; do not add 10 to a d-plus-s count.
Remember

The highest-occupied-shell shortcut is most straightforward for main-group atoms. Some transition-element configurations are exceptions: palladium is in period 5 although its ground state is with 5s empty. A period labels the table’s filling sequence, not an infallible count of occupied shells.

Quiz

Quick check

What produces the similar chemistry of elements in a group?

Quick check

Which sequence explains the length of period 5?

Quick check

How many electrons can a d subshell contain?

Quick check

Where does an atom with outer configuration belong?

Quick check

Why does period 3 contain eight elements rather than eighteen?

Quick check

Which observation warns against treating as a period-length formula?

Practice Problems

Practice Problems
  1. Explain why the p block has six columns and the d region ten.
  2. Derive the lengths of periods 4 and 6 from the orbitals filled.
  3. Write the general outer configuration of Group 1 and explain the use of a noble-gas core.
  4. A proposed ground-state configuration for Ga is . Identify the missing filled subshell, write the corrected configuration, and locate Ga. State what the outer s–p pattern alone already tells you.
  5. An element has outer configuration . Give its period, group, atomic number, and family.
  6. Locate the atom with . Explain why 3d does not put it in period 3.
  7. Explain why members of a group may have similar chemistry but different degrees of reactivity.

Key Takeaways

Key Takeaways

Periodicity follows recurring outer electron configurations. Subshell capacities are 2, 6, 10, and 14 for s, p, d, and f. Period lengths follow the subshells filled in energy order, not the shell-capacity formula alone. Main-group period and group positions can usually be read directly from their outer s and p configurations.