Chemical Thermodynamics · Lesson 1 of 10
Systems, States, and the First Law
“Learn to define a thermodynamic system and account for the energy it receives or gives out.”
• Identify a system, its surroundings, and its boundary. • Distinguish open, closed, isolated, and adiabatic situations. • Explain state variables and internal energy without tracking individual particles. • Apply the chemical sign convention to heat and work. • Use the first law to calculate an internal-energy change.
Choosing the system
A fuel can warm a saucepan, turn an engine, or supply electrical energy through a cell. These effects look different, yet each involves energy being transferred or transformed. Thermodynamics studies such changes using the measurable properties of large collections of particles. Its starting point is a choice: exactly which part of the situation will we study?
The system is the matter or region selected for study. The surroundings are everything outside that selection; in practice we focus on the part that can interact with it. Together they form the thermodynamic universe.
For a reaction in a beaker, we might choose the reacting mixture as the system. The beaker, air, and laboratory then belong to the surroundings. A boundary separates the two. It can be a real wall or an imaginary surface around a chosen volume. Changing the selection changes the bookkeeping, so state it before discussing heat, work, or matter flow.
An uncovered reacting mixture is an open system because material may enter or leave and energy may cross the boundary. A sealed conducting vessel is closed: it keeps its matter but can exchange heat. An ideally sealed and insulated vessel is isolated. A real thermos approximates isolation for a limited time; no everyday container insulates perfectly.
A process with no heat transfer across the system boundary, so . Work may still cross an adiabatic boundary. An insulated gas compressed by a moving piston is therefore adiabatic without being isolated.
Problem
Classify water in an uncovered saucepan, in a sealed metal vessel, and in an ideal sealed rigid insulated vessel.
- 1.Choose the water and any water vapour inside the selected boundary as the system.
- 2.In the uncovered saucepan, evaporation transfers matter out and the surroundings can transfer heat in: the system is open.
- 3.The sealed metal vessel prevents matter transfer but conducts heat: it is closed.
- 4.The ideal sealed rigid insulated vessel permits neither matter transfer nor heat transfer nor boundary work: it is isolated under the stated conditions.
Describing a state
Following the position and speed of every molecule would be impossible in a chemical calculation. Instead we describe a state using bulk properties such as pressure, volume, temperature, amount, and composition. At equilibrium these macroscopic properties remain steady. Thermodynamics relates equilibrium states and the energy changes between them; it does not by itself tell us how fast a reaction reaches its final state.
A property whose value is determined by the present state of the system. Its change depends on the initial and final states, rather than on the route between them. Pressure, volume, temperature, and internal energy are examples.
Not every state variable is independent. For a fixed amount of ideal gas, specifying its pressure and temperature fixes its volume through the gas equation. For a reacting mixture, the composition must also be known. Two samples at the same temperature need not have the same energy if they contain different amounts or different substances.
Problem
Water starts at and ends at . One route heats it directly; another cools it first and then heats it. Compare the temperature changes.
- 1.For either route, the change is final temperature minus initial temperature.
- 2.Thus ; a temperature interval has the same numerical size in kelvin and degrees Celsius.
- 3.The intermediate cooling changes the route but not the endpoints. The net temperature change is therefore the same.
- 4.The total heat exchanged along the routes need not be the same if their other process conditions differ. A state-function change does not make every energy transfer path independent.
Internal energy, heat, and work
Atoms and molecules have energy associated with motion, interactions, and their internal structures. Internal energy, represented by , includes the microscopic energy of the system. We usually cannot assign its absolute value experimentally. We can determine a change, , by measuring energy transferred to or from a suitably defined system.
Joule compared mechanical stirring of insulated water with electrical heating through a resistor. When equal amounts of work produced the same final state from the same initial state, the measured temperature changes agreed. The route for doing work differed, but the resulting internal-energy change was fixed by the endpoints. In an adiabatic experiment all the transferred energy is work, so .
Energy transferred because of a temperature difference, represented by . Heat flows spontaneously from a warmer region to a cooler one. A system contains internal energy; heat describes energy crossing a boundary.
Energy transfer by an organised interaction with the surroundings, represented by . Mechanical compression and electrical energy supplied through a resistor are examples. Work is also a transfer, rather than a substance stored inside the system.
The chemical sign convention keeps the system at the centre of the account. Heat absorbed by it is positive; heat released is negative. Work done on it is positive; work done by it is negative. The signs describe direction, not whether an interaction is useful or desirable.
| Transfer | Sign | Effect when it is the only energy transfer |
|---|---|---|
| Heat enters the system | Internal energy increases | |
| Heat leaves the system | Internal energy decreases | |
| Surroundings do work on system | Internal energy increases | |
| System does work on surroundings | Internal energy decreases |
Conserving energy
A system can receive heat and work during the same process. Its net energy gain is the algebraic sum of both transfers. For a closed system with negligible changes in its overall kinetic and gravitational potential energies, the first law gives the internal-energy change in this form.
In an isolated system both transfers are zero, so its internal energy stays constant. Energy can still change form or redistribute inside it. For example, chemical energy can become thermal energy without energy appearing from nowhere. For a fixed pair of states, and may individually change with the route, but their sum must equal the same .
Problem
Find if (a) 1.00 kJ of work is done on an adiabatic system, (b) a rigid closed system releases 250 J of heat without other work, and (c) a system absorbs 701 J of heat while doing 394 J of work.
- 1.In (a), and , so .
- 2.In (b), heat leaves the system, so ; the stated absence of work gives . Thus .
- 3.In (c), heat enters, so . Work is done by the system, so .
- 4.Therefore . The system gains energy because the heat received exceeds the work it gives out.
Adiabatic means zero heat transfer, not zero temperature change. Closed means zero matter transfer, not zero heat or work. Also, a gas at high temperature is not said to “contain heat”: its energy is a state property, while heat and work describe transfers.
Quiz
Which boundary allows energy transfer but prevents matter transfer?
What must be zero during an adiabatic process?
Why is internal energy a state function?
A system releases 80 J of heat while 120 J of work is done on it. What is its internal-energy change?
Which statement about two routes between the same states is correct?
Practice Problems
- Define the system and surroundings for a burning candle if the wax and flame are chosen as the system. Identify possible matter and energy transfers.
- Explain why an insulated cylinder with a moving piston can be adiabatic without being isolated.
- A system absorbs 450 J of heat and does 160 J of work. Find its internal-energy change.
- A closed system loses 1.20 kJ of internal energy while 0.30 kJ of work is done on it. Determine the heat transferred, including its sign.
- One route between two states has and . On another route . Find q on the second route and explain why it differs.
- Explain what thermodynamics can and cannot tell us about fuel burning in an engine.
Key Takeaways
Choose the system before assigning a sign to an energy transfer. Open, closed, isolated, and adiabatic describe different exchange conditions. Internal energy is a state function; heat and work are path-dependent transfers. For the stated closed-system conditions, energy conservation is expressed by .
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Pressure–Volume Work and Gas Expansion