Exploring Algebraic Identities · Lesson 4 of 8
More Identities
“More identities, because algebra apparently has several clever disguises.”
• Derive (a+b+c)². • Visualise the three-variable square identity. • Use the identity in calculation. • Understand a²−b²=(a+b)(a−b). • Use the difference-of-squares form for quick squaring.
The Square of Three Terms
Let d=b+c. Then (a+b+c)² becomes (a+d)², so we can use an identity we already know.
The identity has three square terms and three pairwise products, each doubled because each pair appears twice in full multiplication.
Problem
Use 119=100+10+9.
- 1.119²=100²+10²+9²+2(100)(10)+2(10)(9)+2(9)(100).
- 2.=10000+100+81+2000+180+1800.
- 3.=14161.
Difference of Squares
Multiplying the right side gives a²−ab+ab−b², so the middle terms cancel.
A Useful Rearrangement
The chapter connects this form with Śhrīdharāchārya and rapid calculation of squares. Choosing b as a small convenient difference can turn a square into an easy product.
Problem
Use the rearranged identity.
- 1.Choose a=55 and b=5.
- 2.55²=(60)(50)+25.
- 3.=3000+25=3025.
Practice Problems
- Expand (p+3q+7r)².
- Expand (3x−2y+4z)².
- Find 117² using a suitable identity.
- Find 198² using a suitable identity.
- Find 1104² using a suitable identity.
- Use the difference-of-squares rearrangement to calculate 35², 65² and 85².
- Factor 16y²−24y+9.
Key Takeaways
• (a+b+c)² has three square terms and three doubled pair-products. • Substitution can reduce a new identity to a known one. • a²−b²=(a+b)(a−b). • Difference of squares is useful for factorisation and fast calculation. • Geometric models help explain identities, not merely memorise them.
Next, we use algebra tiles to see multiplication and factorisation as rectangular area.