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Lesson 12 of 13

Quadrilaterals · Lesson 12 of 13

Which Quadrilateral Is It?

“Classify quadrilaterals using overlapping properties, set relationships and counterexamples.”

Learning Objectives

• Classify figures from sufficient combinations of properties. • Use counterexamples to test claims. • Connect overlapping quadrilateral families. • Solve mixed construction, angle and congruence problems.

You now know several names for four-sided figures, and many of their properties overlap. A square has equal diagonals, but so does a non-square rectangle. A rhombus has perpendicular diagonals, but some kites do too. The challenge is to decide what the given information actually guarantees. Start by listing the facts, then ask whether a different kind of figure could satisfy them as well.

This lesson brings the earlier ideas together. You will use definitions, triangle congruence, parallel-line reasoning and counterexamples, rather than choosing a name only from the way a diagram looks.

Figure it Out

A property can be true for every member of a family without identifying that family uniquely. Equal diagonals are a rectangle property, but the full diagonal test also requires mutual bisection. A sufficient condition includes enough information to force the conclusion.

To disprove a statement about every figure, one valid counterexample is enough. To prove it, explain why the given conditions force the result in every case. A few successful measurements do not complete that proof.

Given informationStrongest guaranteed familyWhy
Four right anglesRectangleThis is the angle definition; sides need not all be equal.
Four equal sidesRhombusThis is the side definition; angles need not be right angles.
Diagonals bisect each otherParallelogramOpposite small triangles are congruent by SAS.
Equal diagonals that bisect each otherRectangleThe isosceles-triangle argument gives four right angles.
Perpendicular diagonals that bisect each otherRhombusFour congruent small right triangles give equal sides.
Equal, perpendicular, mutually bisecting diagonalsSquareBoth rectangle and rhombus conditions hold.

In a Venn diagram, put rectangles and rhombuses inside parallelograms, with their overlap labelled squares. Under the kite definition used here, rhombuses lie inside kites too. A kite that is also a parallelogram must have all four sides equal: adjacent equalities from the kite and opposite equalities from the parallelogram connect all the sides.

A kite can also be a rectangle: its adjacent-side equalities, together with the rectangle’s opposite-side equalities, force four equal sides. With four right angles as well, the figure is a square.

Definition check

The supplied answer key says no quadrilateral can be both a kite and a rectangle. That conflicts with the stated kite definition AB = BC and CD = DA: a square satisfies it and is also a rectangle. We follow the stated definition, so the answer is yes—a square. This source inconsistency is flagged rather than silently copied.

A counterexample

Problem
Must equal, bisecting diagonals give a square?

Proving the opposite-side test

Problem
A quadrilateral has AB = CD and BC = DA. What must it be?

Opposite angles as a test

Problem
Both pairs of opposite angles are equal. Must the quadrilateral be a parallelogram?

PAOIRDS30°PAIR and RODS are rectangles; O lies on AI.
Overlapping rectangles PAIR and RODS
An angle between overlapping rectangles

Problem
PAIR and RODS are rectangles. O lies on AI and ∠ORI = 30°. Find ∠IOD.

A square inside a square

Problem
In square CASE, U, X, W and V are the midpoints of CA, AS, SE and EC. What is the boundary U–X–W–V?

CASEUXWVJoin the midpoints in boundary order: U–X–W–V.
The midpoint square inside square CASE
The concave quadrilateral

Problem
Does an inward-pointing quadrilateral still have angle sum 360°?

ClaimVerdictReason
Equal, bisecting diagonals force a square.FalseA non-square rectangle is a counterexample.
Three right angles force a rectangle.TrueThe fourth angle is 360° − 270° = 90°.
Mutually bisecting diagonals force a parallelogram.TrueSAS gives equal alternate angles and parallel opposite sides.
Perpendicular diagonals force a rhombus.FalseA kite can have one diagonal bisected but not the other.
Both pairs of opposite angles equal force a parallelogram.TrueThe angle sum makes adjacent pairs supplementary.
All four angles equal force a rectangle.TrueEach angle is 360° ÷ 4 = 90°.
Every isosceles trapezium is a parallelogram.FalseEqual non-parallel legs do not provide a second parallel pair.

Quiz

Quick check

Which quadrilateral is both a rectangle and a rhombus?

Quick check

Equal, bisecting diagonals guarantee a:

Quick check

Perpendicular diagonals alone guarantee a rhombus.

Quick check

If both pairs of opposite angles are equal, the quadrilateral is a:

Quick check

Four equal sides plus one 90° angle force a:

Practice Problems

Practice Problems
  1. A quadrilateral has equal diagonals that bisect each other. Give the strongest guaranteed name.
  2. Its diagonals bisect each other at 90° and have unequal lengths. Classify it.
  3. A quadrilateral has four equal sides and equal diagonals. Classify it.
  4. Give a counterexample to “perpendicular diagonals imply rhombus.”
  5. Which figures belong to both the kite and rectangle families under our definitions? Explain.
Practice 1: worked solution

1. Equality and mutual bisection are the rectangle diagonal test. 2. The figure is a rectangle. It could be a square, but a square is not guaranteed.

Practice 2: worked solution

1. Perpendicular mutual bisection gives four equal sides, so it is a rhombus. 2. Unequal diagonals exclude a square, so it is a non-square rhombus.

Practice 3: worked solution

1. Four equal sides make it a rhombus, so its diagonals bisect each other at 90°. 2. The added equal-diagonal condition now supplies all three square conditions. 3. It is a square.

Practice 4: worked solution

1. Construct AC with AO = OC = 3 cm and perpendicular BD with BO = 3 cm, DO = 5 cm. 2. The boundary is a kite and the diagonals are perpendicular. 3. But BO ≠ DO, contradicting the mutual bisection required in a rhombus. Thus this kite is a counterexample.

Practice 5: worked solution

1. In a kite, AB = BC and CD = DA. In a rectangle, AB = CD and BC = DA. 2. Together these imply all four sides are equal; the rectangle also supplies four right angles. 3. The common figures are squares, despite the conflicting answer-key statement.

Key Takeaways

Key Takeaways

• Use all the given conditions before choosing the strongest guaranteed name. • A property of a family is not always a sufficient test for that family. • One valid counterexample disproves an “always” claim. • Squares are simultaneously rectangles, rhombuses, parallelograms and kites. • Congruence and parallel-line converses justify classification tests. • Concave quadrilaterals retain the 360° total when the reflex interior angle is counted.