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Lesson 3 of 10

Algebra Play · Lesson 3 of 10

Number Pyramids — Finding Missing Numbers

“Solve number pyramids by adding upward, subtracting backward, and forming equations for missing entries.”

Learning Objectives

• Apply the addition rule of a number pyramid to fill known values upward. • Work backwards from upper values using subtraction. • Represent an unknown pyramid entry with a variable and form equations from the structure. • Solve a pyramid equation and use the result to complete every remaining box. • Check a completed pyramid by verifying every parent box against the two boxes below.

A number pyramid is a diagram in which each box is determined by the two boxes directly below it. The rule is simple, but missing entries can force us to reason in different directions. Sometimes we add upward, sometimes we subtract downward, and sometimes algebra is the cleanest route.

The Pyramid Rule

Definition
Number pyramid

A layered arrangement in which every box above the bottom row equals the sum of the two adjacent boxes directly below it.

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A completed three-row number pyramid— Check that 1 + 9 = 10, 9 + 4 = 13, and 10 + 13 = 23.

When the entire bottom row is known, completing the pyramid is straightforward: add adjacent pairs to create the next row, then continue upward. The top depends on every value beneath it.

Building upward

Problem
The bottom row is 3, 5, 2. Complete the three-row pyramid.

  1. 1.Add the first adjacent pair: 3 + 5 = 8.
  2. 2.Add the second adjacent pair: 5 + 2 = 7.
  3. 3.The top is 8 + 7 = 15.
  4. 4.The completed rows are 3, 5, 2; then 8, 7; then 15.

Working Backwards with Subtraction

If an upper box and one of its children are known, the other child can be found by subtraction. If a + b = 10 and a = 4, then b = 10 - 4 = 6. This is simply undoing addition.

Finding missing lower boxes

Problem
A three-row pyramid has top 10. The left box in the middle row is 4, and the left box on the bottom is 1. Find all missing values.

  1. 1.The two middle boxes add to 10. If the left middle box is 4, the right middle box is 10 - 4 = 6.
  2. 2.The left middle box 4 is made from bottom-left 1 plus bottom-middle. So bottom-middle = 4 - 1 = 3.
  3. 3.The right middle box 6 is bottom-middle 3 plus bottom-right. So bottom-right = 6 - 3 = 3.
  4. 4.The completed bottom row is 1, 3, 3.
Common mistake

Subtraction is used only when you know a sum and one addend. Do not automatically subtract whenever you move down; first identify the exact equation represented by the three connected boxes.

When a Variable Is More Efficient

Some pyramids do not give enough information for a single subtraction to unlock everything. In that case, give one unknown a letter. Every connected box can then be written in terms of that letter, and the top condition creates an equation.

Solving the 12, c, 8 pyramid

Problem
The bottom row is 12, c, 8 and the top is 60. Find c and complete the pyramid.

  1. 1.The left middle box is 12 + c.
  2. 2.The right middle box is c + 8.
  3. 3.These two middle boxes add to the top: (12 + c) + (c + 8) = 60.
  4. 4.Combine like terms: 20 + 2c = 60.
  5. 5.Subtract 20: 2c = 40. Divide by 2: c = 20.
  6. 6.The middle row is 32 and 28, and 32 + 28 = 60.
Three-row pyramid topLaTeX
For bottom-row values a, b, c, the middle entry b contributes to both boxes above it.

The formula a + 2b + c is useful, but it should not replace understanding the diagram. The coefficient 2 appears because the middle bottom value participates in two adjacent sums.

Checking a Completed Pyramid

  1. Start at the bottom-left pair and check that their sum matches the box above.
  2. Move one pair to the right and repeat.
  3. Continue through every row.
  4. If one check fails, locate the first box whose value is inconsistent rather than rebuilding the whole pyramid.
  5. Finally verify that the top agrees with the row immediately below it.
Try this

Construct a three-row pyramid with bottom row 4, 7, 5. Then erase two entries, give the puzzle to someone else, and decide whether the remaining information is sufficient to recover a unique pyramid.

When Is a Pyramid Uniquely Determined?

A pyramid can contain too little information to determine a unique answer. For example, if only the top of a three-row pyramid is known, many different bottom rows can produce that top. Even knowing one bottom value may still leave several possibilities. A well-posed puzzle must provide enough independent information to pin down the missing entries.

This is an important algebra lesson: an equation such as a+2b+c=20 has three unknowns but only one condition, so it has many solutions. A diagram may look constrained, but we should count the actual relationships rather than assume every blank has one answer.

Quiz

Quick check

In a number pyramid, what operation is used to create a box from the two directly below it?

Quick check

If two child boxes are 7 and 9, what is their parent box?

Quick check

A parent box is 18 and one child is 11. What is the other child?

Quick check

For bottom row a, b, c, what is the top of a three-row pyramid?

Quick check

If the bottom row is 12, c, 8 and the top is 60, what is c?

Practice Problems

Practice Problems
  1. Complete a three-row pyramid whose bottom row is 6, 4, 3.
  2. A three-row pyramid has top 24, middle-left 9, and bottom-left 5. Find all remaining entries.
  3. The bottom row is 7, x, 11 and the top is 50. Find x.
  4. The bottom row is p, 6, 8 and the top is 34. Find p.
  5. Create a pyramid puzzle with exactly one unknown bottom entry and a known top. Solve it algebraically.
  6. Explain why the middle bottom entry is counted twice in the expression for the top.

The middle row is 10 and 7, so the top is 17.

Key Takeaways

Key Takeaways

• Each pyramid box is the sum of the two adjacent boxes directly below it. • Known lower values are combined by addition; missing lower values can often be recovered by subtraction. • A variable is useful when several missing entries depend on the same unknown quantity. • For bottom row a, b, c, the top is a + 2b + c. • Always verify a solution by checking every parent box against its two children.