Arithmetic Expressions · Lesson 7 of 7
Chapter Summary and Practice
“Connect expression structure, signed terms and distribution, then apply them together in a full chapter review.”
• Connect expressions, values, equality, brackets and signed terms. • Choose among term evaluation, regrouping, compensation and distribution. • Explain the reasons behind the chapter’s main properties. • Diagnose errors involving signs, bracket scope, repeated quantities and units. • Solve mixed modelling, comparison and expression-creation problems with justified steps.
Connect the Whole Chapter
An expression is more than a string of symbols: it describes a calculation and often a real situation. The chapter has developed ways to read that structure, preserve it through valid rewrites and choose an efficient route to its value. In this review, focus on why a method applies and how you can check its result.
Start by separating the expression from its value. For example, 12 + 8 and 4 × 5 are different instructions with the same value, 20. Equality connects those values; comparison asks which complete value is larger. Brackets and operation conventions then determine the structure of a more complex instruction. In 7 + 3 × (5 − 2), the outer terms are 7 and 3 × (5 − 2), not five unrelated numbers.
| Idea | Useful rule or reasoning | Brief example | Common mistake |
|---|---|---|---|
| Expression and value | An expression describes a calculation; evaluate it to find its value. | 12 + 8 = 4 × 5 = 20 | Assuming equal expressions must look identical. |
| Brackets and terms | Read the grouping and keep each outer signed term complete. | 7 + 3 × (5 − 2) has terms 7 and 3 × (5 − 2) | Adding a factor as though it were a separate term. |
| Additive inverse | Subtracting a number adds its opposite. | 18 − 7 = 18 + (−7) | Dropping a subtraction sign when listing terms. |
| Swapping and grouping | Addition permits swapping or grouping complete signed terms. | −8 + 15 + 8 = (−8 + 8) + 15 | Swapping unsigned numbers in a difference. |
| Removing brackets | Adding preserves inner signs; subtracting reverses them. | 40 − (12 − 3) = 40 − 12 + 3 | Keeping the inner minus after subtracting a difference. |
| Compensation | Track the changes in all affected signed terms. | 307 − 68 = 310 − 71 | Changing only one quantity and claiming equality. |
| Distribution | A factor applies to every inner term; a common factor can be collected. | 6 × (20 − 1) = 120 − 6 | Multiplying only the first term. |
| Modelling and units | Repeat the full unit and inspect any special final step. | Seven deliveries: 7 × (9 + 11) kg | Counting pages when asked for stories, or including a final slip. |
| Creating expressions | Check both the target and the stated number rules. | (4 + 4 + 4) ÷ 4 = 3 | Using an extra digit or an unstated operation. |
The Main Relationships and Their Reasons
The chapter’s formulas express actions you can picture with collections, tokens and repeated groups. Think of a negative term as a loss, then preserve that complete term whenever you rearrange a sum. Think of a multiplying factor as repeating a whole group, so every part of the group must be repeated.
An arithmetic expression combines numbers and operations; its value is the result. Equality compares values as the same. A term is a complete outer additive piece with its sign. The additive inverse of a number is its opposite under addition, so the two sum to zero.
The letters a, b and c in the relationships below stand for numbers, which may include negatives. In products, adjacent letters mean multiplication. The first relationships allow us to treat subtraction as signed addition, then swap or group additive terms. They do not assert that subtraction or division can be swapped or regrouped freely.
These relationships work together. For instance, 6 × 19 + 6 can be seen as 6 × 19 + 6 × 1, then collected into 6 × (19 + 1) = 120. Alternatively, expand 6 × 19 as 6 × (20 − 1) = 120 − 6 and let the final +6 cancel it. One method collects groups; the other expands and groups signed terms. Both preserve the expression’s value.
Choose a Method, Then Check It
An efficient method begins with reading, not with the first operation that catches your eye. Identify brackets and complete terms, decide whether a property simplifies them, and only then calculate. Check the final value against the meaning, units and expected direction of any change.
- State the requested quantity and its unit if there is a story.
- Read bracket scope and identify complete outer signed terms.
- Evaluate inner brackets, products and quotients, or choose a valid rewrite that makes them easier.
- Combine signed term values; use regrouping, cancellation, compensation or distribution where helpful.
- Check by another route or by reasoning about size, signs, groups and units.
Problem
Evaluate 12 + 4 × (18 − 3) − 12 in two ways.
- 1.The outer terms are 12, 4 × (18 − 3) and −12. Group the first and last terms: 12 + (−12) = 0.
- 2.The remaining term is 4 × 15 = 60.
- 3.Alternatively, distribute first: 12 + 4 × 18 − 4 × 3 − 12 = 12 + 72 − 12 − 12.
- 4.Group 12 with one −12, leaving 72 − 12 = 60. The factor 4 applied to both terms inside the bracket.
Problem
Compare 7 × (40 − 2) + 5 with 7 × 40 − 8 without evaluating both fully.
- 1.Distribute the first: 7 × 40 − 14 + 5 = 7 × 40 − 9.
- 2.The second is the same shared product 7 × 40 with only 8 removed.
- 3.Removing 9 leaves one less than removing 8. Therefore the first expression is smaller by 1.
- 4.A numerical check gives 271 and 272. The comparison was already decided by the small corrections.
Problem
Three friends each buy a ₹28 sandwich and a ₹12 drink. Together they pay ₹200. Find their change in two ways.
- 1.One complete order costs 28 + 12 = ₹40. The three orders cost 3 × (28 + 12) = ₹120.
- 2.Change is 200 − 3 × (28 + 12) = 200 − 120 = ₹80.
- 3.Alternatively, distribute the cost: 3 × 28 + 3 × 12 = 84 + 36 = 120, then subtract both costs: 200 − 84 − 36 = ₹80.
- 4.The factor 3 belongs to both items. Subtracting only one drink cost would not describe three complete orders.
Problem
Given 48 × 25 = 1200, evaluate 49 × 25 − 19.
- 1.One extra group of 25 gives 49 × 25 = 1200 + 25 = 1225.
- 2.Subtract 19 by subtracting 20 and restoring 1: 1225 − 20 + 1 = 1206.
- 3.Both adjustments have clear meanings: add one group of 25, then remove 19. You can check by (50 − 1) × 25 − 19 = 1250 − 25 − 19 = 1206.
Find and Repair Common Errors
An incorrect rewrite often looks plausible because most symbols remain familiar. Compare the structure before and after: did a sign move with its term, did a factor reach every part, and did the same quantity remain grouped? Repair the reasoning as well as the numerical answer.
| Incorrect claim | What changed incorrectly | Repair |
|---|---|---|
| 52 − 17 = 17 − 52 | The negative sign did not stay with 17. | 52 + (−17) = (−17) + 52 = 35 |
| 60 − (25 − 5) = 60 − 25 − 5 | Subtracting a reduced amount was treated as removing both parts. | 60 − 25 + 5 = 40 |
| 4 × (20 + 3) = 4 × 20 + 3 | Only one part of the repeated group was multiplied. | 4 × 20 + 4 × 3 = 92 |
| (18 − 7) − 2 = 18 − (7 − 2) | Subtraction grouping changed the removed quantity. | 11 − 2 = 9, whereas 18 − 5 = 13 |
| Five two-page stories = 10 stories | The expression counts pages instead of stories. | There are 5 stories and 10 pages. |
| A snail gains 1 cm per cycle, so a 10 cm post needs 10 days | The final climb was forced to include an unnecessary slip. | Track daytime height; with +3 cm and −2 cm it reaches the top on day 8. |
Number puzzles need an additional kind of check. A construction can have the right value but use a number twice or include an operation that was not allowed. Conversely, a target may be impossible under the stated rules, as with some four-4 targets. State the restrictions, verify every digit use and accept a well-defined limit rather than silently changing the puzzle.
Check Your Understanding
Try each question before opening the explanations. A useful answer includes the reason for your choice, not just its letter.
Quiz
Which gives the correct outer terms of 25 − 3 × (6 + 2) + 4?
Which expression has the same value as 64 − (18 − 7)?
Which equality is justified by collecting a common factor?
Without calculating complete totals, compare 602 − 89 and 605 − 92.
Six friends each buy a ₹15 snack and a ₹9 drink. Which expression gives their change from ₹200?
Which uses exactly three 3s and has value 2?
The whole negative product is one term. Its bracket remains inside that term.
Work these problems on paper and explain any rewrite you use. Open the matching solution after you have made a first attempt; more than one valid expression or method may be possible.
Practice Problems
- Write four expressions with value 24, then give one story for any one of them.
- Name the signed terms and evaluate 7 + 5 × (8 − 2) − 12 ÷ 3.
- Evaluate −16 + 9 + 16 − 4 using convenient grouping. Name the properties used.
- Remove brackets and evaluate 72 − (30 − 8) + (14 − 6).
- Use distribution to calculate 98 × 35, then check by separating 35 into 30 + 5.
- Compare 9 × 52 − 10 with 9 × (52 − 2) without fully calculating.
- A shop packs 84 kg of grain into 3 kg packets and adds five existing packets. Write and evaluate the total packet count.
- A club reads one four-page story on five days per week for seven weeks. Find stories and pages, keeping the two expressions distinct.
- A snail climbs 5 m daily and slips 3 m nightly on a 13 m post. Find the first day it reaches the top and justify the final step.
- Using exactly four separate 4s with +, −, ×, ÷ and brackets, make 3 and 15. Explain how you checked the rules.
- Three friends each buy a ₹32 item and a ₹18 item. They add one combined ₹5 tip and pay ₹200. Find their change in two ways.
- Explain why 307 − 68 = 310 − 71 and why 307 + 68 is not equal to 310 + 71.
Examples: 18 + 6, 30 − 6, 4 × 6 and 48 ÷ 2. Four trays with six cups each match 4 × 6. Other correct expressions and stories are valid.
Key Takeaways
• Read an expression’s structure and the situation before calculating. • Keep signs attached to complete terms; products and quotients may be single terms. • Addition permits swapping and grouping signed terms, but subtraction does not permit arbitrary changes. • Removing brackets must preserve the meaning of adding or subtracting the whole quantity. • Distribution connects repeated groups, common factors and mental multiplication. • Track units, repeated quantities, special final steps and puzzle constraints as part of checking an answer.
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Applying and Creating Expressions
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