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Lesson 10 of 12

Coordination Compounds · Lesson 10 of 12

Bonding in Metal Carbonyls

“Explain how CO donation and metal back-donation cooperate, and connect bonding with representative carbonyl structures.”

Learning Objectives

• Identify terminal and bridging carbonyl ligands. • Explain the directions of σ donation and π back-donation. • Relate back-donation to metal–carbon and carbon–oxygen bond strengths. • Describe the structures and formal metal states of representative carbonyls.

A neutral ligand can bind a low-oxidation-state metal

Carbon monoxide is neutral, yet it forms stable complexes with many transition metals in low formal oxidation states. Ni(CO)₄, Fe(CO)₅ and Cr(CO)₆ are familiar examples. If every CO is assigned charge zero and the entity is neutral, the formal metal oxidation state is zero. That formal assignment does not mean there is no electron-density redistribution. Oxidation states are bookkeeping integers, whereas real bonding involves continuous sharing and polarisation of electron density.

Terminal CO attaches to one metal through carbon. A metal–carbonyl unit is usually approximately linear at M–C–O because the donor and acceptor orbitals overlap effectively along that direction. Drawing the metal attached to oxygen instead would represent a different and unusual binding situation, not the ordinary carbonyl ligand being taught here. A bridging carbonyl attaches to more than one metal and needs a different structural picture.

Two complementary electron-density transfers

Two reinforcing interactions in M–CO bondingMCOCO → M: σ donationM → CO π*: back-donationBack-donation strengthens M–C but weakens internal C–O.
σ donation and π back-donation in an ordinary metal carbonyl— Original schematic; not to scale. Enlarge to inspect labels.

In σ donation, an occupied CO orbital with substantial carbon lone-pair character overlaps with an accepting metal orbital. Electron density flows from CO toward the metal along the M–C axis. In π back-donation, an occupied metal d orbital of suitable symmetry overlaps with an empty antibonding π* orbital on CO. Electron density flows from metal toward ligand. The arrows in the diagram label orbital interactions, not a stepwise chemical reaction mechanism.

Definition
Synergic bonding

Mutually reinforcing ligand-to-metal σ donation and metal-to-ligand π back-donation. Both interactions contribute to the metal–carbon bond, while back-donation populates an antibonding orbital of the C–O bond.

σ donation supplies electron density to the metal and can facilitate back-donation. Back-donation in turn helps accommodate that density and strengthens the metal–ligand interaction. Populating CO π* weakens the internal C–O bond, often lengthening it and lowering its stretching frequency relative to free CO. Thus metal–carbon bonding can become stronger while carbon–oxygen bonding becomes weaker. Saying that back-donation strengthens both bonds confuses the interfragment bond with the internal ligand bond.

CO is consequently a strong-field ligand in many complexes, a result that a point-charge model alone cannot explain. The metal and CO do not transfer an entire pair irreversibly in each direction as two independent ionic events. The donation/back-donation language decomposes a shared molecular-orbital interaction into useful components.

Structures with one metal

Mononuclear carbonyl structuresCOCOCOCONiNi(CO)₄: tetrahedralCOCOCOCOCOFeFe(CO)₅: trigonal bipyramidalCOCOCOCOCOCOCrCr(CO)₆: octahedralCO labels represent C-bound ligands; projected bonds show 3D arrangements.
Representative mononuclear carbonyl geometries— Original schematic; not to scale. Enlarge to inspect labels.
ComplexFormal state / d countTerminal CO countEstablished geometry
Ni(CO)₄Ni(0), formal d¹⁰4Tetrahedral
Fe(CO)₅Fe(0), formal d⁸5Trigonal bipyramidal
Cr(CO)₆Cr(0), formal d⁶6Octahedral

In trigonal-bipyramidal Fe(CO)₅, three equatorial CO ligands lie in a plane around the metal with 120° relationships, and two axial CO ligands lie above and below at 180° to one another and 90° to the equatorial directions. Five-coordinate does not always mean this geometry, but this is the established geometry of Fe(CO)₅. In Cr(CO)₆, six CO donors occupy octahedral positions. In Ni(CO)₄, the four CO donors are tetrahedral and all electrons are paired in the formal d¹⁰ description.

Why geometry is not set by ligand identity alone

Problem
CO is present in Ni(CO)₄, Fe(CO)₅ and Cr(CO)₆. Why do they have different geometries?

  1. 1.Each CO supplies a donor interaction and an acceptor channel, but the metal’s valence-electron count and the number of attached ligands also matter.
  2. 2.Four, five and six terminal CO ligands give different donor-position requirements, realised here as tetrahedral, trigonal-bipyramidal and octahedral structures.
  3. 3.The same ligand can therefore participate in different geometries. Neither the word carbonyl nor a generic strong-field label uniquely determines shape.

Two metals: separate bridging from terminal groups

Dimeric carbonyl connectivityMn₂(CO)₁₀COCOCOCOCOMnCOCOCOCOCOMnTen terminal CO; one Mn–Mn bondCo₂(CO)₈, bridged formCOCOCOCoCOCOCOCoCOCOSix terminal + two bridging COConnectivity schematics; carbonyls attach through carbon.Other non-bridged Co₂(CO)₈ forms are known.
Metal–metal bonds and carbonyl bridges in two dimers— Original schematic; not to scale. Enlarge to inspect labels.

Mn₂(CO)₁₀ has a Mn–Mn bond and ten terminal CO ligands, five on each manganese. It can be viewed as two Mn(CO)₅ fragments joined through the metal–metal bond; the five carbonyl positions around each metal form a square-pyramidal fragment. Counting five terminal CO groups at one Mn is not the same as claiming that an isolated Mn(CO)₅ molecule is the complete structure. The metal–metal bond is an additional essential connection.

A commonly depicted form of Co₂(CO)₈ has six terminal CO groups, three on each cobalt, and two bridging CO groups, plus a Co–Co bond. Each bridge is one CO ligand bonded to both metals, so two bridges do not become four separate molecules. Other non-bridged forms are also known, especially depending on conditions. The bridged drawing is a representative structure, not a claim that the formula has only one possible arrangement in every phase.

Check the carbonyl inventory

Problem
A drawing of bridged Co₂(CO)₈ shows three terminal CO groups on each Co and two bridges. Does it match the formula?

  1. 1.Three terminal groups on each of two metals give six terminal CO molecules.
  2. 2.Each of the two bridges is counted once as a molecule, although it has two metal attachments. Total CO count is 6 + 2 = 8.
  3. 3.Both Co–Co and bridge connections must appear. Treating each bridge attachment as an independent CO would incorrectly give ten ligands.

Formal d count and electron sharing

In neutral homoleptic carbonyls with only neutral CO and homonuclear metal–metal bonds, the metals have formal oxidation state zero. The formal d counts are Ni d¹⁰, Fe d⁸, Cr d⁶, Mn d⁷ and Co d⁹ by group-number bookkeeping. These counts do not directly equal the numbers of unpaired electrons in the complete molecules: bonding, metal–metal interactions and orbital filling must be considered. In particular, do not infer paramagnetism of a dimer by treating its metals as isolated free atoms.

The carbonyl model makes the limitations of purely ionic CFT visible. The ligand is neutral but its π-acceptor character has a major influence on bonding and splitting. Keep the two electron-flow directions, actual carbon connectivity and internal C–O antibonding consequence together; learning only the word synergic leaves the chemical explanation incomplete.

Quick Quiz

Quiz

Quick check

In ordinary terminal metal carbonyls, which CO atom binds the metal?

Quiz explanation

The standard carbonyl ligand attaches through carbon.

Quick check

What is the direction of π back-donation?

Quiz explanation

Back-donation transfers electron density into a ligand antibonding orbital.

Quick check

What typically happens to the internal C–O bond with greater back-donation?

Quiz explanation

Population of CO π* reduces internal bond order.

Quick check

Which geometry is established for Fe(CO)₅?

Quiz explanation

Three equatorial and two axial CO ligands give the trigonal-bipyramidal structure.

Quick check

How many distinct CO molecules bridge in the commonly drawn bridged Co₂(CO)₈ form?

Quiz explanation

Six are terminal; two additional CO groups bridge the metal pair.

Practice Problems

Practice Problems
  1. Explain synergic bonding using both orbital occupancy and transfer direction.
  2. Give formal metal oxidation states and geometries for Ni(CO)₄, Fe(CO)₅ and Cr(CO)₆.
  3. Describe Mn₂(CO)₁₀ so that all essential connections are present.
  4. Draw the connectivity of the representative bridged Co₂(CO)₈ structure in words.
  5. A student says neutral CO cannot strongly affect orbital energies. Explain the error.
  6. Why should stronger metal-to-CO back-donation often lower the C–O stretching frequency?

1. Occupied CO carbon-donor character overlaps an accepting metal orbital, giving CO → M σ donation. 2. Filled metal d orbitals overlap empty CO π*, giving M → CO π back-donation. 3. These reinforce metal–carbon bonding; occupation of ligand π* weakens C–O. 4. The description concerns shared orbital interactions, not two isolated ionic reactions.

Key Takeaways

Key Takeaways

• Ordinary terminal CO binds through carbon. • CO is neutral in formal oxidation-state bookkeeping. • σ donation proceeds from CO to metal. • π back-donation proceeds from metal to CO π*. • Synergic interactions strengthen metal–carbon bonding while back-donation weakens C–O. • Carbonyl structures depend on both metal and ligand count. • A bridging CO is one molecule attached to multiple metals. • Representative bridged Co₂(CO)₈ does not exclude known non-bridged forms.