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Lesson 2 of 9

Respiration in Plants · Lesson 2 of 9

Glycolysis: Ten Steps from Glucose to Pyruvate

“EMP pathway, sugar activation, splitting, NADH formation, two ATP investments and four ATP production.”

Learning Objectives

• Trace all ten reactions of the EMP pathway from glucose to pyruvate. • Distinguish energy-investment and energy-payoff phases. • Explain why the six-carbon intermediate splits into two three-carbon molecules. • Identify where ATP is invested, ATP is generated and NADH is formed. • Calculate the net ATP and NADH yield per glucose.

The first shared pathway of glucose breakdown

Glycolysis means 'sugar splitting' and is named for a sequence of reactions that transforms one six-carbon glucose molecule into two three-carbon pyruvate molecules. The pathway is also called the Embden–Meyerhof–Parnas (EMP) pathway, after scientists who described it. It operates in the cytosol of cells and does not directly require molecular oxygen; this is why it can function both when mitochondrial aerobic oxidation is available and when some cells depend on fermentation.

Plants commonly obtain glucose through breakdown of transported sucrose or stored carbohydrates. Invertase can hydrolyse sucrose into glucose and fructose. Sugars then enter central carbohydrate metabolism, although fructose can enter through different enzymatic routes depending on tissue. A common school-level description follows glucose as the starting molecule, with phosphorylation helping trap and process the sugar inside cells.

The two logical phases

The energy-investment phase spends two ATP molecules to phosphorylate and rearrange a six-carbon sugar so it can split into two three-carbon units. The energy-payoff phase processes each three-carbon unit to make NADH and ATP. Because every reaction after the split effectively occurs twice for each starting glucose, students must double the products of the later steps. This 'one glucose → two trioses → two pyruvates' logic prevents many errors in the balance sheet.

Definition
EMP pathway

The ten-step sequence of enzymatic reactions forming two pyruvates from glucose.

Definition
Phosphorylation

Addition of a phosphate group to an organic molecule; it can change reactivity or help retain sugar metabolites in cells.

Step-by-step route through the ten reactions

StepSubstrate → productEnzyme / meaningEnergy or redox change
1Glucose → glucose-6-phosphateHexokinase phosphorylates glucose1 ATP spent
2Glucose-6-phosphate → fructose-6-phosphatePhosphoglucose isomerase rearranges sugarNo ATP directly
3Fructose-6-phosphate → fructose-1,6-bisphosphatePhosphofructokinase-1 adds phosphate1 ATP spent
4Fructose-1,6-bisphosphate → glyceraldehyde-3-phosphate + dihydroxyacetone phosphateAldolase splits six carbons into two triosesNo ATP directly
5Dihydroxyacetone phosphate ⇌ glyceraldehyde-3-phosphateTriose phosphate isomerase yields two GAP equivalentsTwo GAP proceed
62 GAP → 2 1,3-bisphosphoglycerateGAP dehydrogenase oxidises and adds inorganic phosphate2 NAD⁺ → 2 NADH
72 1,3-bisphosphoglycerate → 2 3-phosphoglyceratePhosphoglycerate kinase transfers phosphate to ADP2 ATP produced
82 3-phosphoglycerate → 2 2-phosphoglyceratePhosphoglycerate mutase repositions phosphateNo ATP directly
92 2-phosphoglycerate → 2 phosphoenolpyruvateEnolase removes water2 H₂O released
102 phosphoenolpyruvate → 2 pyruvatePyruvate kinase generates ATP2 ATP produced

How phosphorylation prepares a sugar for splitting

The first hexokinase reaction uses ATP to form glucose-6-phosphate. This six-carbon sugar phosphate cannot pass through most glucose transport pathways in its original form and is committed to intracellular metabolism, although it may be routed into several pathways. The next isomerisation changes the sugar's carbonyl configuration to form fructose-6-phosphate. Phosphofructokinase-1 then spends another ATP to make fructose-1,6-bisphosphate, an important regulated step.

Why spend ATP when the goal is to gain ATP? Phosphorylation makes key intermediates more reactive and positions functional groups for a symmetrical cleavage into three-carbon phosphates. This initial investment creates a pathway whose later oxidation and phosphate-transfer steps can recover more ATP than was spent.

Why the cleavage produces two usable triose units

Aldolase splits fructose-1,6-bisphosphate into glyceraldehyde-3-phosphate (GAP, also called PGAL) and dihydroxyacetone phosphate (DHAP). These products have three carbons each but different arrangements. Triose phosphate isomerase interconverts them so both carbon halves can pass through the same later sequence. Each succeeding event therefore happens twice for one original glucose molecule.

A common mistake is to count only one NADH and one ATP at an energy-yielding step because the diagram shows one reaction arrow. The stoichiometry after the split is doubled. For example, the oxidation of two GAP molecules produces two NADH, not one. This applies equally to both ATP-yielding phosphate-transfer reactions.

How NADH is formed

GAP dehydrogenase catalyses oxidation of each GAP with inorganic phosphate addition to make the high-energy acyl phosphate 1,3-bisphosphoglycerate. NAD⁺ accepts reducing equivalents to form NADH. For one glucose, two GAP molecules yield two NADH molecules. In aerobic cells these reducing equivalents may contribute to mitochondrial electron transport through shuttle systems, while fermentative cells must regenerate NAD⁺ using a different route.

Definition
NAD⁺ / NADH pair

An oxidised/reduced coenzyme pair that carries electron equivalents between metabolic reactions.

Two steps that make ATP directly

In step 7, 1,3-bisphosphoglycerate transfers a phosphate to ADP through phosphoglycerate kinase, making ATP and 3-phosphoglycerate. This is substrate-level phosphorylation because the phosphate comes from a metabolic intermediate rather than from the mitochondrial proton gradient. With two three-carbon molecules, the cell gains two ATP at this step.

After phosphoglycerate mutase and enolase reactions, phosphoenolpyruvate (PEP) retains a high phosphoryl-transfer potential. Pyruvate kinase transfers its phosphate to ADP, producing pyruvate and another two ATP per original glucose. Across both ATP-producing steps, four ATP are formed; the two initially invested leave a net gain of two ATP.

Glycolysis: six carbons become two three-carbon pyruvatesGlucose (6C)Glucose-6-phosphate → fructose-6-PFructose-1,6-bisphosphate (6C)2 triose phosphates (3C each)2 × 1,3-bisphosphoglycerate2 × 3-phosphoglycerate2 × phosphoenolpyruvate2 × pyruvate (3C each)ATP → ADPATP → ADP2 NAD⁺ → 2 NADH2 ADP → 2 ATP2 ADP → 2 ATPInvestment2 ATP spentPayoff4 ATP madeNet per glucose: 2 ATP + 2 NADH + 2 pyruvate
Glycolysis overview: investment, cleavage and energy payoff— The full table lists every intermediate and enzyme; the diagram highlights carbon splitting and energy bookkeeping.

ATP and electron balance per glucose

QuantitySpentProducedNet
ATP242 ATP
NADH022 NADH
Pyruvate022 molecules (3C each)

The net is 4 ATP produced − 2 ATP consumed = 2 ATP per glucose. Two NADH are formed, and two pyruvate molecules are available for subsequent metabolism. No carbon is released as CO₂ within glycolysis itself; all six original carbon atoms are still present in two three-carbon pyruvates. This point helps distinguish glycolysis from pyruvate decarboxylation and the TCA cycle, where carbon dioxide release occurs.

During anaerobic fermentation, NADH is generally reoxidised to NAD⁺ so glycolysis can continue; the ATP yield remains net two per glucose because fermentation's terminal steps usually do not add another net ATP gain. With oxygen and functional mitochondria, pyruvate and its electrons can feed more energy-yielding reactions.

Why glycolysis is widely conserved

Glycolysis does not require a membrane-bound organelle and is found across a great range of organisms. The source notes that early life developed under low-oxygen conditions, making oxygen-independent carbohydrate processing biologically important. The ten-step pathway is deeply conserved but regulation and alternative entry routes differ among species. It is not correct to say glycolysis itself uses oxygen simply because it is part of aerobic respiration.

Substrate-level ATP formation is different from oxidative phosphorylation: glycolytic enzymes directly transfer phosphate from organic intermediates to ADP, while mitochondria use an electrochemical gradient generated by electron transport. Both result in ATP but derive energy through distinct mechanisms.

Frequent calculation and diagram errors

Fructose-1,6-bisphosphate has two phosphate groups on different carbons; 'bis' is not interchangeable with 'di' in its formal chemical name. The triose step creates GAP and DHAP, not two independent six-carbon compounds. The source writes PGAL for glyceraldehyde-3-phosphate and BPGA for 1,3-bisphosphoglycerate; both refer to the same compounds as their longer names. The ATP formed is four gross, but net two after deducting two invested ATP.

Count ATP and NADH without memorising a table

Problem
One glucose gives two triose phosphates. Each triose forms one NADH and two ATP during the payoff phase. If two ATP were invested earlier, what is the total net yield?

  1. 1.Two trioses × 1 NADH = 2 NADH.
  2. 2.Two trioses × 2 ATP = 4 ATP gross.
  3. 3.4 gross ATP − 2 invested ATP = 2 ATP net, together with two pyruvate molecules.

Quick Quiz

Quiz

Quick check

In which compartment does glycolysis take place?

Quick check

How many ATP are used in glycolysis before the cleavage phase?

Quick check

Which sugar is split into two triose phosphates?

Quick check

Which step forms NADH from NAD⁺?

Quick check

What is the net ATP yield of glycolysis per glucose?

Quick check

How many CO₂ molecules leave during glycolysis itself?

Quick check

How many pyruvate molecules are formed from one glucose?

Quick check

Which ATP-forming event exemplifies substrate-level phosphorylation?

Practice Problems

Practice Problems
  1. Trace all ten glycolytic reactions with principal enzymes.
  2. Identify ATP investment, ATP generation and NADH-producing steps.
  3. Why are the late glycolytic yields doubled per glucose?
  4. Calculate glycolysis net yield and carbon balance.
  5. Explain why glycolysis can occur without oxygen and still contribute to aerobic respiration.

Glucose → glucose-6-P (hexokinase) → fructose-6-P (isomerase) → fructose-1,6-bisP (PFK-1) → GAP + DHAP (aldolase) → two GAP (triose isomerase) → 1,3-bisphosphoglycerate (GAP dehydrogenase) → 3-phosphoglycerate (phosphoglycerate kinase) → 2-phosphoglycerate (mutase) → PEP (enolase) → pyruvate (pyruvate kinase).

Key Takeaways

Key Takeaways

• Glycolysis is the cytosolic ten-step EMP pathway turning one 6C glucose into two 3C pyruvates. • The investment phase uses two ATP; the payoff phase makes four ATP, so net ATP is two. • Fructose-1,6-bisphosphate is cleaved into two three-carbon products that converge as GAP. • Two NADH are formed during GAP oxidation to 1,3-bisphosphoglycerate. • ATP formed at phosphoglycerate kinase and pyruvate kinase steps is substrate-level phosphorylation. • Glycolysis itself directly uses no oxygen and releases no CO₂. • Fate of pyruvate and NADH depends on oxygen availability and cell type.