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Lesson 15 of 15

Light – Reflection and Refraction · Lesson 15 of 15

Chapter Summary and Practice

Every ray, mirror and lens returns for one final group photo.

Learning Objectives

• Connect reflection, refraction, mirrors and lenses into one coherent picture. • Recall the important definitions and image-formation cases. • Select and apply every major optical formula correctly. • Use sign conventions to interpret image position, orientation and size. • Solve mixed conceptual and numerical problems with systematic checks.

A ray of light may return from a surface, change direction at a boundary, converge to a real image or appear to spread from a virtual one. The ideas studied across this chapter are not separate tricks. They are one connected system built from ray paths, geometry, material-dependent speed and careful sign conventions.

Core Definitions

TermMeaning
Reflection of lightReturn of light into the same medium after it strikes a surface
NormalLine perpendicular to a surface at the point of incidence
Real imageImage formed by the actual meeting of rays; it can be obtained on a screen
Virtual imageImage formed by the apparent meeting of backward ray extensions; it cannot be obtained on a screen
Spherical mirrorMirror whose reflecting surface forms part of a sphere
Concave mirrorSpherical mirror whose reflecting surface curves inward and can converge parallel rays
Convex mirrorSpherical mirror whose reflecting surface bulges outward and diverges reflected rays
Pole PCentre of the reflecting surface of a spherical mirror
Centre of curvature CCentre of the sphere of which the mirror is a part
Radius of curvature RRadius of that sphere, equal to PC
Principal axisStraight line through P and C for a mirror, or through C₁ and C₂ for a lens
Principal focus FPoint where parallel rays meet or appear to diverge from after reflection or refraction
Focal length fDistance from P or O to the principal focus
ApertureEffective diameter of the reflecting surface or lens outline
Refraction of lightChange in direction at a boundary caused by a change in light speed
Lateral displacementSideways separation between the incident ray's original line and the parallel emergent ray from a slab
Refractive indexSpeed ratio that measures the optical effect of a medium
Optical densityComparison based on refractive index and light speed rather than mass per volume
LensTransparent material bounded by two surfaces, at least one spherical
Convex lensLens thicker at the centre that converges parallel rays
Concave lensLens thinner at the centre that diverges parallel rays
Optical centre OCentral point of a thin lens through which a ray passes with negligible deviation
Magnification mRatio of image height to object height; its sign indicates orientation in the adopted convention
Power of a lensReciprocal of focal length in metres
DioptreUnit of lens power; one dioptre equals one inverse metre

Reflection and Mirrors

Reflection obeys two laws: the incidence angle equals the reflection angle, and the incident ray, reflected ray and normal lie in one plane. Both angles are measured from the normal. A plane mirror forms a virtual, erect, same-sized and laterally inverted image at the same distance behind the mirror as the object is in front.

A concave mirror converges parallel rays at a real focus in front. A convex mirror makes reflected rays diverge as though they came from a focus behind it. For small-aperture spherical mirrors, F lies midway between P and C. Concave mirrors are used when convergence or magnification is needed; convex mirrors are used when an erect image and wide field of view are more valuable.

Law of reflectionLaTeX
i is the angle of incidence and r is the angle of reflection, each measured from the normal.
Mirror radius and focusLaTeX
R and f must use the same unit. The sign follows the Cartesian convention when used in calculations.

Concave-Mirror Image Review

ObjectImage positionSizeNature
At infinityAt FPoint-sizedReal and inverted
Beyond CBetween F and CDiminishedReal and inverted
At CAt CSame sizeReal and inverted
Between C and FBeyond CEnlargedReal and inverted
At FAt infinityNo finite screen imageReflected rays parallel
Between F and PBehind mirrorEnlargedVirtual and erect

Convex-Mirror Image Review

ObjectImage positionSizeNature
At infinityAt F behind mirrorPoint-sizedVirtual and erect
At any finite distanceBetween P and F behind mirrorDiminishedVirtual and erect

Mirror Formula and Magnification

Mirror formulaLaTeX
u is object distance, v image distance and f focal length, measured from P in one consistent unit.
Mirror magnificationLaTeX
h and h′ are object and image heights. Negative m indicates an inverted real image; positive m an erect virtual image here.

Refraction and Refractive Index

A ray entering an optically denser medium obliquely slows and bends toward the normal. Entering an optically rarer medium, it speeds up and bends away. At normal incidence its speed changes but its direction does not. In a rectangular glass slab, equal and opposite bending at parallel faces makes the emergent ray parallel to the incident ray, though laterally displaced.

Optical density is determined by refractive index, not by mass per volume. The larger-index medium carries light more slowly. Snell's law applies to a given colour and pair of media, so reversing the direction reverses the relative index.

Snell's lawLaTeX
n₂₁ is the refractive index of medium 2 with respect to medium 1 for the stated direction of travel.
Relative refractive indexLaTeX
v₁ and v₂ are light speeds in media 1 and 2. Reversing the media gives n₁₂ = 1/n₂₁.
Absolute refractive indexLaTeX
c = 3.0 × 10⁸ m s⁻¹ is vacuum speed and v is speed in the medium. Refractive index has no unit.

Lenses and Image Formation

A convex lens is thicker at the centre and converges parallel rays; a concave lens is thinner at the centre and diverges them. A lens has two centres of curvature, two principal foci and an optical centre. In the thin-lens model, a ray through O passes with negligible deviation.

Convex-Lens Image Review

ObjectImage positionSizeNature
At infinityAt F₂Point-sizedReal and inverted
Beyond 2F₁Between F₂ and 2F₂DiminishedReal and inverted
At 2F₁At 2F₂Same sizeReal and inverted
Between F₁ and 2F₁Beyond 2F₂EnlargedReal and inverted
At F₁At infinityNo finite screen imageEmergent rays parallel
Between F₁ and OObject sideEnlargedVirtual and erect

Concave-Lens Image Review

ObjectImage positionSizeNature
At infinityAt F₁Point-sizedVirtual and erect
At any finite distanceBetween F₁ and ODiminishedVirtual and erect

Lens Formula, Magnification and Power

Lens formulaLaTeX
All distances are measured from O. Convex f is positive and concave f is negative.
Lens magnificationLaTeX
The lens distance form has no leading minus sign. Use the sign of m to interpret orientation.
Lens powerLaTeX
Use f in metres to obtain P in dioptres. Convex P is positive; concave P is negative.
Power of lenses in contactLaTeX
Add powers algebraically, retaining every sign, then use f = 1/P for the effective focal length.

Sign Convention Review

QuantityMirror conventionLens convention
OriginPole POptical centre O
Real object on leftu negativeu negative
Concave focal lengthNegativeNegative
Convex focal lengthPositivePositive
Real imagev negative in front of mirrorv positive on opposite side
Virtual imagev positive behind mirrorv negative on object side
Erect image heighth′ positiveh′ positive
Inverted image heighth′ negativeh′ negative

A Reliable Problem-Solving Method

  1. Sketch the device, object region and likely image before calculating.
  2. List every given quantity with its unit and Cartesian sign.
  3. Choose the mirror, lens, refractive-index or power formula that matches the device.
  4. Rearrange symbolically before inserting numbers.
  5. Keep distances in one unit; use metres specifically for power in dioptres.
  6. Interpret signs and magnitude, then compare the result with the ray-diagram prediction.
Mixed Example

Problem
A concave mirror has f = -12 cm and an object at u = -18 cm. Find image position and magnification.

  1. 1.Use 1/v = 1/f - 1/u = -1/12 + 1/18.
  2. 2.With denominator 36, 1/v = (-3 + 2)/36 = -1/36, so v = -36 cm.
  3. 3.m = -v/u = -(-36)/(-18) = -2.
  4. 4.The image is 36 cm in front, real, inverted and twice enlarged, which matches an object between C and F.
Mixed Example With Refraction

Problem
Light moves through a medium at 2.0 × 10⁸ m s⁻¹. Find its absolute refractive index and state how it compares optically with water of index 1.33.

  1. 1.Use n = c/v with c = 3.0 × 10⁸ m s⁻¹.
  2. 2.n = 3.0 × 10⁸ / 2.0 × 10⁸ = 1.50.
  3. 3.Because 1.50 > 1.33, the medium is optically denser than water and carries light more slowly.
Mixed Example With Lenses

Problem
A +4 D lens and a -1.5 D lens are in contact. Find net power and effective focal length.

  1. 1.Add powers with signs: P = +4 - 1.5 = +2.5 D.
  2. 2.Use f = 1/P = 1/2.5 = +0.40 m = +40 cm.
  3. 3.The positive result means the combination behaves as a converging lens.

Common Confusions

ConfusionCorrection
Angles measured from the surfaceIncidence and refraction angles are measured from the normal
Virtual means invisibleA virtual image is visible but cannot be projected because rays do not actually meet
All focal lengths are positiveConcave mirrors and concave lenses have negative f in the adopted convention
Mirror and lens formulas are interchangeableTheir distance and magnification signs differ
Greater mass density means greater optical densityOptical density depends on refractive index and light speed
Centimetres can be used directly for dioptresConvert f to metres before applying P = 1/f

Quiz

Quick check

Which statement correctly distinguishes a real image from a virtual one?

Quick check

A convex lens object is at 2F₁. Which image forms?

Quick check

Which quantity has no unit?

Quick check

For a mirror, u = -20 cm and v = -40 cm. What is m?

Quick check

Two lenses of +3 D and -5 D are in contact. What is the combination?

Practice Problems

Practice Problems
  1. A convex mirror forms an image 12 cm behind it for an object 48 cm in front. Find magnification and describe the image. Solution: u = -48 cm and v = +12 cm. m = -v/u = -(12)/(-48) = +0.25. It is virtual, erect and one-quarter the object size.
  2. A convex lens has f = +20 cm and u = -30 cm. Find v and m. Solution: 1/v = 1/20 - 1/30 = 1/60, so v = +60 cm. m = v/u = 60/(-30) = -2. The image is real, inverted and twice enlarged.
  3. Light travels from medium A at 2.4 × 10⁸ m s⁻¹ into medium B at 1.8 × 10⁸ m s⁻¹. Find nBA and predict bending. Solution: nBA = vA/vB = 2.4/1.8 = 1.33. B is optically denser, so an oblique ray bends toward the normal.
  4. A lens has power -4 D. Find focal length in metres and centimetres and identify the lens. Solution: f = 1/P = -0.25 m = -25 cm. The negative focal length identifies a concave lens.
  5. A 5 cm object forms a real lens image with magnification -1.5. Find image height and explain the signs. Solution: h′ = mh = -1.5 × 5 = -7.5 cm. The 7.5 cm magnitude shows enlargement; the negative sign shows inversion and therefore a real image in this case.

Key Takeaways

Key Takeaways

• Reflection returns light to the same medium, while refraction changes its direction across media. • Real images form by actual convergence; virtual images form by apparent convergence. • Object position relative to F and C or 2F determines image position, size and nature. • Mirror and lens formulas require different sign relationships. • Refractive index links optical density with light speed, not mass density. • Power is the reciprocal of focal length in metres and powers in contact add algebraically. • Correct units and Cartesian signs must be assigned before substitution. • A final result is trustworthy only when its signs agree with the predicted ray diagram.