Statistics · Lesson 4 of 4
Chapter Summary and Practice
“Mean, mode and median gather for a final tour through grouped data.”
• Recall all formulas for grouped mean, mode and median. • Choose an efficient calculation method. • Distinguish modal class from median class. • Compare the meaning of mean, median and mode. • Solve mixed grouped-data problems.
Mean, median and mode all describe the centre of a distribution, but in different ways. Mean is the arithmetic balance point, median is the middle position, and mode is the most frequent value.
Mean
Mode
Median
Relationship Among the Three Measures
This relationship is empirical. It is useful as an estimate, but it is not an exact identity for every possible distribution.
Which Measure Should You Use?
| Measure | Best interpreted as | Useful when |
|---|---|---|
| Mean | Overall arithmetic average | All values should contribute |
| Median | Middle value | Extreme values may distort the mean |
| Mode | Most frequent value | Most common or most popular value matters |
How to Choose the Right Method
| Clue | Method |
|---|---|
| Small class marks | Direct mean |
| Large class marks | Assumed mean |
| Convenient common factor in deviations | Step-deviation |
| Largest frequency | Mode |
| Middle position / cumulative frequency | Median |
| Known total plus missing frequency | Form an equation using the relevant formula |
• Using class limits instead of class marks for mean, • Dividing by number of classes instead of total frequency, • Reporting the modal class as the mode, • Using the wrong cf in the median formula, • Confusing ordinary frequency with cumulative frequency, • Applying mode or median formulas before making intervals continuous where required,
Guided Practice
Problem
Intervals 500–520, 520–540, 540–560, 560–580, 580–600 have frequencies 12, 14, 8, 6, 10. Find the mean.
- 1.Class marks: 510, 530, 550, 570, 590.
- 2.Take a = 550, h = 20.
- 3.uᵢ = −2, −1, 0, 1, 2.
- 4.fᵢuᵢ = −24, −14, 0, 6, 20, so Σfᵢuᵢ = −12.
- 5.Σfᵢ = 50.
- 6.x̄ = 550 + 20(−12/50) = 545.2.
Problem
Intervals 0–20, 20–40, 40–60, 60–80, 80–100, 100–120 have frequencies 10, 35, 52, 61, 38, 29. Find the mode.
- 1.Modal class = 60–80.
- 2.l = 60, h = 20, f₁ = 61, f₀ = 52, f₂ = 38.
- 3.Mode = 60 + [(61 − 52)/(122 − 52 − 38)] × 20.
- 4.Mode = 65.625.
Problem
Weights 40–45, 45–50, 50–55, 55–60, 60–65, 65–70, 70–75 have frequencies 2, 3, 8, 6, 6, 3, 2. Find the median.
- 1.Cumulative frequencies: 2, 5, 13, 19, 25, 28, 30.
- 2.n = 30, so n/2 = 15.
- 3.Median class = 55–60.
- 4.l = 55, cf = 13, f = 6, h = 5.
- 5.Median = 55 + [(15 − 13)/6] × 5 ≈ 56.67.
Problem
Electricity-use intervals 65–85, 85–105, 105–125, 125–145, 145–165, 165–185, 185–205 have frequencies 4, 5, 13, 20, 14, 8, 4. Compare mean, median and mode.
- 1.Using class marks gives mean ≈ 137.06.
- 2.Cumulative frequencies are 4, 9, 22, 42, 56, 64, 68, so median class = 125–145 and median = 137.
- 3.Modal class = 125–145, giving mode ≈ 135.77.
- 4.The three values are close, but each describes a different feature of the distribution.
Problem
Mean = 42 and median = 45. Estimate the mode.
- 1.Use 3 Median = Mode + 2 Mean.
- 2.135 = Mode + 84.
- 3.Mode = 51.
Quiz
Which value represents a class interval when finding grouped mean?
The modal class is the class with:
To locate the median class, compare cumulative frequencies with:
In the median formula, cf is:
Which measure describes the most common value?
Check that you can calculate class marks, construct cumulative frequencies, identify modal and median classes, choose the correct formula, and explain what each final answer means.
Practice Problems
- Find the mean for intervals 45–55, 55–65, 65–75, 75–85, 85–95 with frequencies 3, 10, 11, 8, 3.
- Find the mode for age intervals 5–15, 15–25, 25–35, 35–45, 45–55, 55–65 with frequencies 6, 11, 21, 23, 14, 5.
- Find the median for electricity-use intervals 65–85, 85–105, 105–125, 125–145, 145–165, 165–185, 185–205 with frequencies 4, 5, 13, 20, 14, 8, 4.
- If median = 28.5 for classes 0–10, 10–20, 20–30, 30–40, 40–50, 50–60 with frequencies 5, x, 20, 15, y, 5 and total 60, find x and y.
- Find mean, median and mode for surname-length intervals 1–4, 4–7, 7–10, 10–13, 13–16, 16–19 with frequencies 6, 30, 40, 16, 4, 4.
- If mean = 35 and median = 38, estimate the mode.
- If mean = 52 and mode = 46, estimate the median.
- Which measure would you choose for the most popular shoe size sold by a store, and why?
- Which measure would you choose for a typical household income when a few incomes are extremely high, and why?
Key Takeaways
• Mean uses all classes and their class marks. • Mode estimates the most frequent value. • Median locates the middle of the distribution using cumulative frequency. • Good table construction makes most grouped-data questions much easier.
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Median of Grouped Data
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